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3 years ago

Write an equation in point slope and slope intercept form of a line that passes through the given point and

Mathematics

1 answer:

nekit [7.7K]3 years ago

7 0

Answer:

Point slope is ( Y+4) = 1/2(x+3)

Slope intercept is Y = 1/2(x) -5/2

Step-by-step explanation:

For the point slope form.

Given the point as (-3,-4)

And the gradient m = 1/2

Point slope form is

(Y - y1) = m(x-x1)

X1 = -3

Y1 = -4

(Y - y1) = m(x-x1)

(Y - (-4)) = 1/2(x -(-3))

( Y+4) = 1/2(x+3)

For the slopes intercept form

Y = mx + c

We can continue from where the point slope form stopped.

( Y+4) = 1/2(x+3)

2(y+4)= x+3

2y + 8 = x+3

2y = x+3-8

2y = x-5

Y = x/2 - 5/2

Y = 1/2(x) -5/2

Where -5/2 = c

1/2 = m

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3 years ago

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Answer:

The 95% confidence interval for those opposed is: (0.298, 0.334).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

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For this problem, we have that:

1786 of the 2611 were in favor, so 2611 - 1786 = 825 were opposed. Then

$n = 2611, \pi = \frac{825}{2611} = 0.316$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.316 - 1.96\sqrt{\frac{0.316*0.684}{2611}} = 0.298$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.316 + 1.96\sqrt{\frac{0.316*0.684}{2611}} = 0.334$

The 95% confidence interval for those opposed is: (0.298, 0.334).

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scZoUnD [109]

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