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Natali5045456 [20]
3 years ago
13

Evaluate the expression when y=-4 y^2+5y+1

Mathematics
1 answer:
Maru [420]3 years ago
8 0

Step-by-step explanation:

❀ \underline{ \underline{ \text{Given}}} :

  • y = -4

❀ \underline{ \underline{ \text{To \: find}}} :

  • Value of y² + 5y + 1

❀ \underline{ \underline{ \text{Solution}}} :

~Plug the value of y at first :

➾ \sf{ {-4}^{2}  + 5 \times (-4 )+ 1}

~ Evaluate the power : 4²

➾ \sf{16 + 5 \times (-4 )+ 1}

Follow the BODMAS { Bracket , Of , Division , Multiplication , Addition and Subtraction } rule :

~Multiply -5 and 4

➾ \sf{16 + (-20)+ 1}

~ Multiply the signs : ( + ) and ( - ) :

➾ \sf{16 - 20 + 1}

~Add the numbers : 16 and 1

➾ \sf{17-20}

~ Subtract 20 from 17

➾ \sf{-3}

\pink{ \boxed{ \boxed{ \tt{⟿ \: Our \: final \: answer : -3}}}}

Hope I helped ! ♡

Have a wonderful day / night ツ

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3y+4=11y PLEASE STEP BY STEP: SHOW WORK PLEASE AND THANK YOU !!
bija089 [108]
3y + 4 = 11y
(take away 3y from both sides)
4         = 8y
(divide by 8 on both sides)
0.5      = y

y = 0.5

4 0
3 years ago
Read 2 more answers
Someone plz help this is due today
-Dominant- [34]

3x+5x+1=17

x=2

y=5•2+1

y=1

(x, y)=(2, 11)

3x+2(4x+5)=43

x=3

y=4•3+5

y=17

(x, y)=(3, 17)

I think I did it right and I hope I helped you

3 0
3 years ago
How to solve 3 and 1/2 + 5 and 1/2
zheka24 [161]

Answer:

9

Step-by-step explanation:

first add 3 and 5       =8

then add 1/2 and 1/2      =1

8+1 =9

5 0
4 years ago
Find the perimeter of a triangle with vertices A(3, 1), B(2, -1), and C(-3, 2). Leave
natulia [17]

The perimeter of triangle is: 14.15 units

Step-by-step explanation:

First of all we have to find the lengths of sides of triangles

Given

A(3, 1), B(2, -1), and C(-3, 2)

The distance formula will be used to find the lengths of sides

d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\

So,

AB = \sqrt{(2-3)^2+(-1-1)^2}\\=\sqrt{(-1)^2+(2)^2}\\=\sqrt{1+4}\\=\sqrt{5}\\=2.24\ unitsBC = \sqrt{(-3-2)^2+(2+1)^2}\\=\sqrt{(-5)^2+(3)^2}\\=\sqrt{25+9}\\=\sqrt{34}\\= 5.83\ units\\AC = \sqrt{(-3-3)^2+(2-1)^2}\\=\sqrt{(-6)^2+(1)^2}\\=\sqrt{36+1}\\=\sqrt{37}\\=6.08\ units

The perimeter of triangle will be:

P = AB+BC+AC\\= 2.24+5.83+6.08\\=14.15\ units

Hence,

The perimeter of triangle is: 14.15 units

Keywords: Triangle Perimeter

Learn more about perimeter at:

  • brainly.com/question/573729
  • brainly.com/question/572693

#LearnwithBrainly

7 0
3 years ago
Find the equation of the line that is parallel and passes through the point (9,6) find the equation of the line perpendicular
masya89 [10]
Any line parallel to this line can be written as y=-2/3x+c and passes through (9,6).thus 6=-2/3(9)+c.c-6=6.c=12.equation is y=-2/3x+12.
3 0
3 years ago
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