Answer:
Find the Roots (Zeros) f(x)=x^3-6x^2+13x-20. f(x)=x3−6x2+13x−20 f ( x ) = x 3 - 6 x 2 + 13 x - 20. Set x3−6x2+13x−20 x 3 - 6 x 2 + 13 x - 20 equal to 0 0 .
Step-by-step explanation:
hope this helps
The 2 lines are parallel, so the 2 sides(e.g. 1 and 2/ 3 and 49) add up = 180 and In this case the 2 sides are equal as u can see from the original diagram so the angle of 2 is 180-49=131.
x² - x - 12 ≠ 0
x² - 4x + 3x - 12 ≠ 0
x (x - 4) + 3 (x - 4) ≠ 0
(x + 3)(x - 4) ≠ 0
x ≠ -3 or x ≠ 4
(B)
Answer:
x - m/q = t
x = m/q + t is the answer