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Rainbow [258]
2 years ago
12

Please i need help with this

Mathematics
1 answer:
Goshia [24]2 years ago
8 0

Answer:

B.

Step-by-step explanation:

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Express log2 64-log2 4 as a simple logarithm
Triss [41]
<span>Express log(2)64-log(2)4 as a single logarithm.
Simplify as possible.
Solution: 

 = log(2)[64/4] 
= log(2)[16]
= 4
</span>
4 0
3 years ago
Which expression is equivalent to (5^-2)(5^-1)
nadya68 [22]
The rule for multiplying similar bases with exponents:

(a^b)(a^c)=a^(b+c)

In this case we have:

(5^-2)(5^-1)

5^(-2-1)

5^(-3)

The rule for negative exponents:

a^(-b)=1/(a^b)

So in this case:

5^(-3) is equal to 

1/(5^3)

1/125
5 0
3 years ago
Read 2 more answers
I WILL MARK BRAINLIEST IF YOU CAN ANSWER THISSSS (9x10)/44+pi = xy what is xy and how did you find your answer?? After typing pl
melomori [17]

Answer:  1.9

Step-by-step explanation:

You want to multiply 9x10 which is 90.

Then you want to add 44+pi

now pi can be shown as 3.14 or 22 over 7

in this case you want to add 44 + 3.14 which gives you 47.14

now you want to divide 90/47.14 which gives you 1.90920661858 or in short

1.9

6 0
3 years ago
5n + 3n<br> simplify each expression
Setler79 [48]

Answer: 8n

Step-by-step explanation: 5n + 3n

3 0
3 years ago
For what value of x is the function g(x)=x/1-x NOT defined?
VMariaS [17]

The function is definately defined at x=0 but not x=1.

But its just one part of the coordinate (x,y).

If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.

Now I hope you understood what I meant!

Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:

6 0
3 years ago
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