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Rainbow [258]
2 years ago
12

Please i need help with this

Mathematics
1 answer:
Goshia [24]2 years ago
8 0

Answer:

B.

Step-by-step explanation:

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Fine the sum of 2/9+3/5​
Arturiano [62]

Answer:

0.82

اولويات الضرب و القسمه

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2 years ago
The two triangles below are similar. What is the similarity ratio of ΔABC to ΔDEF?
Evgesh-ka [11]
It would be a 2:1 ratio because sides AC and DF are 8:4 which simplifies to 2:1

Hope this helps!
5 0
3 years ago
Read 2 more answers
Practice: Organizing Information
Naya [18.7K]
B^n / b^m = b^(n - m)

4^5 / 4^2 = 4^(5 - 2) = 4^3
5 0
3 years ago
Nate is constructing a tangent line to a circle he drew from a point outside the circle. Once he has the circle and the point is
Tema [17]

Answer:

The next step is to find the point on the circle which makes a tangent line that passes through the outside point.

Step-by-step explanation:

A tangent line to a circle is a line that touches the circle at exactly one point. You need two points to draw a line. You already have one point and the circle, then you need the other point, which lies on the circle. These two points have to lie on the same line. Notice that there are two possible tangent lines.

8 0
3 years ago
A bin is constructed from sheet metal with a square base and 4 equal rectangular sides. if the bin is constructed from 48 square
kondaur [170]
This is a problem of maxima and minima using derivative.

In the figure shown below we have the representation of this problem, so we know that the base of this bin is square. We also know that there are four square rectangles sides. This bin is a cube, therefore the volume is:

V = length x width x height

That is:

V = xxy = x^{2}y

We also know that the <span>bin is constructed from 48 square feet of sheet metal, s</span>o:

Surface area of the square base = x^{2}

Surface area of the rectangular sides = 4xy

Therefore, the total area of the cube is:

A = 48 ft^{2} =  x^{2} + 4xy

Isolating the variable y in terms of x:

y =  \frac{48- x^{2} }{4x}

Substituting this value in V:

V =  x^{2}( \frac{48- x^{2} }{x}) = 48x- x^{3}

Getting the derivative and finding the maxima. This happens when the derivative is equal to zero:

\frac{dv}{dx} = 48-3x^{2} =0

Solving for x:

x =  \sqrt{\frac{48}{3}} =  \sqrt{16} = 4

Solving for y:

y =  \frac{48- 4^{2} }{(4)(4)} = 2

Then, <span>the dimensions of the largest volume of such a bin is:
</span>
Length = 4 ft
Width =  4 ft
Height = 2 ft

And its volume is:

V = (4^{2} )(2) = 32 ft^{3}

8 0
3 years ago
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