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3 years ago

Is it true that (-3b)^4=12b^4

Mathematics

2 answers:

Marianna [84]3 years ago

5 0

Yes, it is true. I hope I'm not helping you cheat....lol.

AleksAgata [21]3 years ago

4 0

<span>(-3b)^4=12b^4
This a true statement.

HOPE THIS HELPS! ^_^</span>

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What is the median of this data set? {29, 22, 23, 31, 29, 29, 22, 23} Enter your answer in the box.

GaryK [48]

Answer:

The median is 26

Step-by-step explanation:

A "median" is equivalent to, when the terms are arranged in the proper order, whichever term is in the "middle".

So- first, arrange the terms in ascending order.

[22, 22, 23, 23, 29, 29, 29, 31]

There are an even number- eight- terms in total, so we will take the average of the two "middle" terms.

(29+23)/2; 29 and 23 are the "middle" terms, and there are two of them.

(52)/2 = 26

Therefore, the median is 26.

I hope this helped! :)

4 0

2 years ago

Please assist me with this problem

n200080 [17]

Answer:

The answer to your question is 90 dB

Step-by-step explanation:

Data

I = 10⁻³

I⁰ = 10⁻¹²

Formula

Loudness = 10log ( $\frac{I}{Io}$ )

Process

1.- To solve this problem, just substitute the values in the equation and do the operations.

2.- Substitution

Loudness = 10 log $(\frac{10^{-3}}{10^{-12}} )$

3.- Simplify

Loudness = 10log (1 x 10⁹)

Loudness = 10(9)

Loudness = 90

7 0

3 years ago

What is the lcm of 5,6, and 7

BigorU [14]

The least common multiple (LCM) of 5, 6, and 7 is 210.

5 × 42 = 210
6 × 35 = 210
7 × 30 = 210

7 0

3 years ago

Read 2 more answers

What is 2 1/4 ÷ 1/2=

marshall27 [118]

Answer:

Step-by-step explanation:

Convert mixed fraction to improper fraction.

$2\frac{1}{4}$ ÷ $\frac{1}{2}$ = $\frac{9}{4}$ ÷ $\frac{1}{2}$

Now use K C F method

K - Keep the first fraction

C - Change the division operation to multiplication

F- Flip the second number

$= \frac{9}{4} *\frac{2}{1}\\\\= \frac{9}{2}*1\\\\= \frac{9}{2}\\\\= 4 \frac{1}{2}$

4 0

3 years ago

Hi okay no question hello

Svetach [21]

Hey how are you doing

7 0

3 years ago

Read 2 more answers