Answer:
The 99.9% confidence interval for the population proportion is (0.548, 0.896).
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of
, and a confidence level of
, we have the following confidence interval of proportions.
![\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}](https://tex.z-dn.net/?f=%5Cpi%20%5Cpm%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D)
In which
z is the zscore that has a pvalue of
.
For this problem, we have that:
![n = 72, \pi = \frac{x}{n} = \frac{52}{72} = 0.722](https://tex.z-dn.net/?f=n%20%3D%2072%2C%20%5Cpi%20%3D%20%5Cfrac%7Bx%7D%7Bn%7D%20%3D%20%5Cfrac%7B52%7D%7B72%7D%20%3D%200.722)
99.9% confidence level
So
, z is the value of Z that has a pvalue of
, so
.
The lower limit of this interval is:
![\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.722 - 3.29\sqrt{\frac{0.722*0.278}{72}} = 0.548](https://tex.z-dn.net/?f=%5Cpi%20-%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.722%20-%203.29%5Csqrt%7B%5Cfrac%7B0.722%2A0.278%7D%7B72%7D%7D%20%3D%200.548)
The upper limit of this interval is:
![\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.722 + 3.29\sqrt{\frac{0.722*0.278}{72}} = 0.896](https://tex.z-dn.net/?f=%5Cpi%20%2B%20z%5Csqrt%7B%5Cfrac%7B%5Cpi%281-%5Cpi%29%7D%7Bn%7D%7D%20%3D%200.722%20%2B%203.29%5Csqrt%7B%5Cfrac%7B0.722%2A0.278%7D%7B72%7D%7D%20%3D%200.896)
The 99.9% confidence interval for the population proportion is (0.548, 0.896).
Answer:
3rd option (bottom left)
Step-by-step explanation:
Answer:
23. Calculate the P-value for this hypothesis test. Assume the requirements for the test are satisfied.
0.087
29. Which of the following pairs of hypotheses is the most appropriate for addressing this question?
H0:p=0.2 Ha:p>0.2
Step-by-step explanation
test statistic: 6.579
You reject Ha
Answer:
(-12, -20).
Step-by-step explanation:
A dilation of factor 4 moves (-3, 5) to (-3*4, 5*4) = the point (-12, 20).
A reflection over the x-axis is (x, y) ------> ( x, -y).
So ( -12, 20) goes to (-12, -20).
B
Step-by-step explanation: