Answer:
F is reduced by 31%
Step-by-step explanation:
F = 1/(d²)
now, we increase the distance by 20% (multiply by 1.2).
F new = 1/(1.2×d)² = 1/(1.44×d²) = (1/1.44) × (1/(d²)) =
= 1/1.44 × old F = 0.69 × old F
100 - 69 = 31%
Use the chain rule to compute the second derivative:
![f(x)=\ln(\sin(2x))](https://tex.z-dn.net/?f=f%28x%29%3D%5Cln%28%5Csin%282x%29%29)
The first derivative is
![f'(x)=(\ln(\sin(2x)))'=\dfrac{(\sin(2x))'}{\sin(2x)}=\dfrac{\cos(2x)(2x)'}{\sin(2x)}=\dfrac{2\cos(2x)}{\sin(2x)}](https://tex.z-dn.net/?f=f%27%28x%29%3D%28%5Cln%28%5Csin%282x%29%29%29%27%3D%5Cdfrac%7B%28%5Csin%282x%29%29%27%7D%7B%5Csin%282x%29%7D%3D%5Cdfrac%7B%5Ccos%282x%29%282x%29%27%7D%7B%5Csin%282x%29%7D%3D%5Cdfrac%7B2%5Ccos%282x%29%7D%7B%5Csin%282x%29%7D)
![f'(x)=2\cot(2x)](https://tex.z-dn.net/?f=f%27%28x%29%3D2%5Ccot%282x%29)
Then the second derivative is
![f''(x)=(2\cot(2x))'=-2\csc^2(2x)(2x)'](https://tex.z-dn.net/?f=f%27%27%28x%29%3D%282%5Ccot%282x%29%29%27%3D-2%5Ccsc%5E2%282x%29%282x%29%27)
![f''(x)=-4\csc^2(2x)](https://tex.z-dn.net/?f=f%27%27%28x%29%3D-4%5Ccsc%5E2%282x%29)
Then plug in π/4 for <em>x</em> :
![f''\left(\dfrac\pi4\right)=-4\csc^2\left(\dfrac{2\pi}4\right)=-4](https://tex.z-dn.net/?f=f%27%27%5Cleft%28%5Cdfrac%5Cpi4%5Cright%29%3D-4%5Ccsc%5E2%5Cleft%28%5Cdfrac%7B2%5Cpi%7D4%5Cright%29%3D-4)
Answer:
the answer is 2
Step-by-step explanation:
The numbers as powers of 5 are 5^-1, 5^-2, 5^-3 and 5^0
<h3>How to rewrite the numbers as a power of 5?</h3>
The numbers are given as:
• 0.2
• 0.04
• 125^-1
• 15^0
<u>Number 1: 0.2</u>
Express as fraction
1/5
Apply the power rule of indices
5^-1
<u>Number 2: 0.04</u>
Express as fraction
1/25
Express 25 as 5^2
1/5^2
Apply the power rule of indices
5^-2
<u>Number 3: 125^-1</u>
Express as fraction
1/125
Express 125 as 5^3
1/5^3
Apply the power rule of indices
5^-3
<u>Number 4: 15^0</u>
Evaluate the exponent
15^0 = 1
Express 1 as 5^0
15^0 = 5^0
Hence, the numbers as a power of 5 are 5^-1, 5^-2, 5^-3 and 5^0
Read more about exponents at
brainly.com/question/847241
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Answer:
the answer is 15 words after 3 weeks
Step-by-step explanation: