Answer:
The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
Step-by-step explanation:
The formula from the maximum distance of a projectile with initial height h=0, is:

Where
is the initial velocity.
In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is
. The critical points of the function are those who make
:


The critical value inside the interval is
.

The second step is to find the values of the function at the endpoints of the interval:

The biggest value of f is gived by
, therefore
is the absolute maximum.
In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of
.
A. 7
b. -2
c. 1-3s
7-3(s+2)
7-3s-6
1-3s
The sum of a number and 6.
Or
The sum of n and 6
Answer:
6 Cut Minimum
Step-by-step explanation:
According to the Question,
You have a 3x3x3 cube.
- First make two cuts parallel to base of the cube each at a distance of 1 unit . This leaves you with three cuboids of dimensions 3x3x1.
- Now make two parallel cuts parallel to the height of the cube. This leaves you with nine cuboids of dimensions 3x1x1.
- Now make the final two cuts each 1 unit apart parallel to width and you are left with 27 cubes of 1x1x1.
So , the final answer is 6 cuts.