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2 years ago

Sophia drops her pencil in a cup and

Mathematics

1 answer:

MariettaO [177]2 years ago

4 0

Answer:

5cm

Step-by-step explanation:

Since the pencil would only fit diagonally, the diameter would have to be half its length. The pencil is 10 centimeters long and 5 centimeters would be half of it.

Note:

Pls notify me if my answer is incorrect for the other users that will see this message. Thank you.

-kiniwih426

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Point Ais a representation of which number on the number line? 0 T -3 1

irinina [24]

Answer:

B = -3

Step-by-step explanation:

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3 years ago

The first four multiples of 7 are 7, 14 21, and 28. Use this example to help you as you answer the questions below.

Pachacha [2.7K]

Answer:

For A. it would be 9, 18, 27, 36, 45, 54

For B. it would be 12, 24, 36, 48, 60, 72

For C. it would be 36

For D. it would be 3

Step-by-step explanation:

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2 years ago

10(x - 5) = -80 i don't understand math that well lol

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3 years ago

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jeunesse earned $725 dollars by working 5 days in a week. What is the average amount that she earned per day?

dem82 [27]

The average amount that Jeunesse earned per day is $145.
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3 years ago

A recent broadcast of a television show had a 10 share, meaning that among 6000 monitored households with TV sets in use, 10%

Kisachek [45]

Answer:

Null and alternative hypothesis

$H_0: \pi \geq0.25\\\\H_1: \pi$

Test statistic $z=-26.82$

P-value $P=0$

The null hypothesis is rejected.

It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

Step-by-step explanation:

We have to perform a hypothesis test of a proportion.

The claim is that less than 25% were tuned into the program, so we will state this null and alternative hypothesis:

$H_0: \pi \geq0.25\\\\H_1: \pi$

The signifiance level is 0.01.

The sample has a proportion p=0.1 and sample size of n=6000.

The standard deviation of the proportion, needed to calculate the test statistic, is:

$\sigma_p=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.25(1-25)}{6000} } =0.0056$

The test statistic is calculated as:

$z=\frac{p-\pi+0.5/N}{\sigma_p} =\frac{0.1-0.25+0.5/6000}{0.0056}=\frac{-0.1499}{0.0056} =-26.82$

As this is a one-tailed test, the P-value is P(z<-26.82)=0. The P-value is smaller than the significance level (0.01), so the effect is significant.

Since the effect is significant, the null hypothesis is rejected. It is concluded that the proportion of households tuned into the program is less than 25%. The claim of the advertiser is rigth and got statistical support.

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2 years ago