Find the common factor and rewrite. Type your answer in the box. Do not use any spaces.

Pls help I’ll brainlest

Ksju [112]

2) G
3) E
4) A
5) E
6) C

3 0

3 years ago

This algebra I need help with all of them

charle [14.2K]

Answer:

17-18) Can you type out the questions for 17-19, I can't read them.

20) a. rational

21) d. 25 in^2

4 0

3 years ago

PLEASE HELP ME OUT!! I WILL MARK BRAINLIEST!!!

melamori03 [73]

Answer:

Step-by-step explanation:

What are you looking for?

3 0

3 years ago

Ms. Carey grades 4 tests during her lunch. She grades 1/3 of the remainder after school. If she syill5has 16 test to grade after

enot [183]

Answer: 24 tests

Step-by-step explanation:

Ms. Carey graded 1/3 of the tests and still had 16 tests to go.

This means that the 16 tests represent the remaining proportion of the total number of tests:

= 1 - 1/3

= 2/3

2/3 of the total is equal to 16 tests. Assuming the total is x, the expression would be:

2/3x = 16

x = 16 ÷ 2/3

x = 16 * 3/2

x = 24 tests

3 0

3 years ago

Because of the relatively high interest rates, most consumers attempt to pay off their credit card bills promptly. However, this

BigorU [14]

Answer:

a. 0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

b. 0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

c. 0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

d. An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 27 dollars and a standard deviation of 9 dollars.

This means that $\mu = 27, \sigma = 9$

A. What proportion of the bank's Visa cardholders pay more than 29 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 29, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{29 - 27}{9}$

$Z = 0.22$

$Z = 0.22$ has a p-value of 0.5871.

1 - 0.5871 = 0.4129

0.4129 = 41.29% of the bank's Visa cardholders pay more than 29 dollars in interest.

B. What proportion of the bank's Visa cardholders pay more than 35 dollars in interest?

This is 1 subtracted by the p-value of Z when X = 35, so:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{35 - 27}{9}$

$Z = 0.89$

$Z = 0.89$ has a p-value of 0.8133.

1 - 0.8133 = 0.1867

0.1867 = 18.67% of the bank's Visa cardholders pay more than 35 dollars in interest.

C. What proportion of the bank's Visa cardholders pay less than 14 dollars in interest?

This is the p-value of Z when X = 14. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{14 - 27}{9}$

$Z = -1.445$

$Z = -1.445$ has a p-value of 0.0742.

0.0742 = 7.42% of the bank's Visa cardholders pay less than 14 dollars in interest.

D. What interest payment is exceeded by only 18% of the bank's Visa cardholders?

This is the 100 - 18 = 82nd percentile, which is X when Z has a p-value of 0.82, so X when Z = 0.915.

$Z = \frac{X - \mu}{\sigma}$

$0.915 = \frac{X - 27}{9}$

$X - 27 = 0.915*9$

$X = 35.2$

An interest payment of $35.2 is exceeded by only 18% of the bank's Visa cardholders.

7 0

3 years ago