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mezya [45]
3 years ago
15

Helppp plzzz idk I need help​

Mathematics
1 answer:
spin [16.1K]3 years ago
3 0

Answer:

<em>T</em><em>h</em><em>e</em><em> </em><em>c</em><em>o</em><em>r</em><em>r</em><em>e</em><em>c</em><em>t</em><em> </em><em>a</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em> </em><em>i</em><em>s</em><em> </em><em>y</em><em>.</em>

Step-by-step explanation:

<em>h</em><em>o</em><em>p</em><em>e</em><em> </em><em>i</em><em>t</em><em> </em><em>w</em><em>o</em><em>r</em><em>k</em><em>s</em><em> </em><em>o</em><em>u</em><em>t</em><em> </em><em>!</em><em>!</em>

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Identify the factors of x2 − 4x − 21. (x − 7)(x 3) (x 7)(x − 3) (x 21)(x − 1) (x − 21)(x 1)
Tanzania [10]

The factors of the quadratic expression x² - 4x - 21 is <u>(x - 7)(x + 3)</u>, making the <u>first option</u> the right choice.

A quadratic expression is of the form ax² + bx + c, which can be factorized using the mid-term factorization method, where b is shown as the sum or difference of two such numbers, whose product is equal to the product of a and c.

In the question, we are asked to factorize the quadratic expression, x² - 4x - 21.

In the given expression, a = 1, b = -4, and c = -21.

Thus, ac = -21.

The numbers having a product 21 are:

1*21 = 21,

3*7 = 21.

Since, 3 - 7 = -4 (That is b), we break b into 3 and -7.

Thus, the expression can now be shown as:

x² - 4x - 21

= x² + (3 - 7)x - 21

= x² + 3x - 7x - 21

= x(x + 3) - 7(x + 3) {By taking common}

= (x - 7)(x + 3) {By taking common}.

Thus, the factors of the quadratic expression x² - 4x - 21 is <u>(x - 7)(x + 3)</u>, making the <u>first option</u> the right choice.

Learn more about factorizing a quadratic expression at

brainly.com/question/52959

#SPJ1

5 0
1 year ago
Find the area of the region that lies inside the first curve and outside the second curve. r = 6 − 6 sin θ, r = 6
yan [13]
Each curve completes one loop over the interval 0\le t\le2\pi. Find the intersections of the curves within this interval.

6-6\sin\theta=6\implies 1-\sin\theta=1\implies \sin\theta=0\implies \theta=0,\theta=\pi

The region of interest has an area given by the double integral

\displaystyle\int_\pi^{2\pi}\int_6^{6-6\sin\theta}r\,\mathrm dr\,\mathrm d\theta

equivalent to the single integral

\displaystyle\frac12\int_\pi^{2\pi}\bigg((6-6\sin\theta)^2-6^2\bigg)\,\mathrm d\theta

which evaluates to 9\pi+72.

8 0
3 years ago
Need help on 7-10 lol pls!!
Afina-wow [57]

Answer:

sorry i dont know :(

Step-by-step explanation:

sorry :(

3 0
3 years ago
What is the answer to this?
ella [17]
Your answer is 3/8 , that’s your answer
5 0
3 years ago
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What are the coefficient(s)in the following expressions?
Tju [1.3M]
The correct answer is C. 5, 6, -7
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