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3 years ago

What is the equation of the line that passes through the point (-4,-7) and has a

Mathematics

1 answer:

Fed [463]3 years ago

4 0

Answer:

y= $\frac{3}{2}$ x-1

Step-by-step explanation:

y=mx+b

-7= $\frac{3}{2}$ (-4)+b

-7=(-6)+b

b=(-1)

y= $\frac{3}{2}$ x-1

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What is 5(2 + x) = 5 ?

Alex787 [66]

5(2+x)=5

or, 10+5x=5

or, 5x= -5

or, x= -1

Hope it helps

8 0

3 years ago

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Eighty percent of the students in a class (group A) share 40% of the candy equally. The remaining 20% of the students (group B)

mestny [16]

Answer:

1/6

Step-by-step explanation:

There is x candy in total and y students in total.

Group A consists of 0.8y students, and group B consists of 0.2y students.

Group A gets 40% of x, or 0.4x. Each student in group A gets 0.4x/(0.8y) = 0.5x/y candy per person.

Group B gets 60% of x, or 0.6x. Each student in group B gets 0.6x/(0.2y) = 3x/y candy per person.

The ratio of candy each student in group A has to the amount of candy each student in group B has is:

(0.5x/y)/(3x/y) = 0.5/3 = 1/6

4 0

4 years ago

Read 2 more answers

In the diagram, line AB is parallel to line CD. Assume that ∠b = 6x + 8 and that ∠g = 4x + 12. Find the value of x.

meriva

The answer is c I think so

3 0

3 years ago

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Two gears are adjusted so that the smaller gear drives the larger one. if the smaller gear of 3.7cm rotates through an angle of

zepelin [54]

Answer:

<em>The larger gear will rotate through 156°</em>

Step-by-step explanation:

<u>Arc Length</u>

The arc length S of an angle θ on a circle of radius r is:

$S = \theta r$

Where θ is expressed in radians.

The smaller gear of r1=3.7 cm drives a larger gear of r2=7.1 cm. The smaller gear rotates through an angle of θ1=300°.

Convert the angle to radians:

$\displaystyle \theta_1=300*\frac{\pi}{180}=\frac{5\pi}{3}$

The arc length of the smaller gear is:

$\displaystyle S_1=\frac{5\pi}{3}\cdot 3.7$

$\displaystyle S_1=\frac{18.5\pi}{3}$

The larger gear rotates the same arc length, so:

$\displaystyle S_2=\frac{18.5\pi}{3}$

$\displaystyle \theta_2\cdot r_2=\frac{18.5\pi}{3}$

Solving for θ2:

$\displaystyle \theta_2=\frac{18.5\pi}{3r_2}$

$\displaystyle \theta_2=\frac{18.5\pi}{3*7.1}$

$\theta_2=2.73\ radians$

$\displaystyle \theta_2=2.73*\frac{180}{\pi}=156$

The larger gear will rotate through 156°

7 0

3 years ago

Covert 4 centimeters into meters .

frutty [35]

4 ÷ 100 = 0.04 meters

3 0

3 years ago

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