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pishuonlain [190]
3 years ago
10

a research company polled a random sample of 799 US teens about internet use. 49% of those teens reported that they had misrepre

sented their age online to gain access to websites and online services. The 95% confidence interval for this number is from 45.6% to 52.5%. Interpret the interval in this contexct. choose the best answer. A. there is a 95% chance that, if one were to ask all teens whether they had misrepresented their age online, 49% of them would say they have. B. there is a 95% chance that if one were to ask all the teens whether they had misrepresented their age online 49% would say they have. C. One is 95% cofident that of the 799 teens polled between 45.6% and 52.5% of them said that they had misrepresented their age online. D. one is 95% cofident that if one were to ask all teens whether they had misrepsresented their age online between 45.6% and 52.5% of them would say they have.
Mathematics
1 answer:
olasank [31]3 years ago
8 0

Answer: One is​ 95% confident​ that, if one were to ask all teens whether they had misrepresented their age​ online, between​ 45.6% and​ 52.5% of them would say they have.

Step-by-step explanation:

A 95% confidence interval interprets that a person is 95% sure that the true population proportion lies in it.

Given : A research company polled a random sample of 799 US teens about internet use.

49% of those teens reported that they had misrepresented their age online to gain access to websites and online services.

The 95% confidence interval for this number is from 45.6% to 52.5%.

i.e. A per son can be 95% sure that the  true proportion of all teens who admit to misrepresenting their age online is between​ 45.6% and​ 52.5%.

Correct interpretation of interval :  

One is​ 95% confident​ that, if one were to ask all teens whether they had misrepresented their age​ online, between​ 45.6% and​ 52.5% of them would say they have.

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