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4 years ago

Plzzzz helpppp asapppppp will mark brainliest

Mathematics

2 answers:

neonofarm [45]4 years ago

6 0

It's a 45-45-90 triangle,

where the legs are congruent, and the hypotenuse is sqrt(2) times the length of a leg.

34kurt4 years ago

5 0

It’s a 45-45-90 triangle, you can tell because two sides are the same and one side is different like the triangle described in the problem

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Exsplain too please, how has your day been btw?

bogdanovich [222]

Answer:

2⁹

Step-by-step explanation:

${2}^{5} \times {2}^{4} \\ = {2}^{5 + 4} \\ = {2}^{9}$

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3 years ago

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To manufacture a light fixture, a company bends 6.56.5 feet of metal tubing into a circle. What is the radius of this circle?

kap26 [50]

3.14 is pi
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4 years ago

Which expression is equivalent to square root 55x^7y6/11x^11y^8

Novay_Z [31]

Answer:

$\large\boxed{\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\dfrac{\sqrt5}{x^2y}}$

Step-by-step explanation:

$\sqrt{\dfrac{55x^7y^6}{11x^{11}y^8}}=\sqrt{\dfrac{55}{11}\cdot\dfrac{x^7}{x^{11}}\cdot\dfrac{y^6}{y^8}}\qquad\text{use}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\=\sqrt{5x^{7-11}y^{6-8}}=\sqrt{5x^{-4}y^{-2}}\qquad\text{use}\ \sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\=\sqrt5\cdot\sqrt{x^{-4}}\cdot\sqrt{y^{-2}}=\sqrt5\cdot\sqrt{x^{(-2)(2)}}\cdot\sqrt{y^{(-1)(2)}}\qquad\text{use}\ (a^n)^m=a^{nm}\\\\=\sqrt5\cdot\sqrt{(x^{-2})^2}\cdot\sqrt{(y^{-1})^2}\qquad\text{use}\ \sqrt{a^2}=a$

$=\sqrt5\cdot x^{-2}\cdot y^{-1}\qquad\text{use}\ a^{-n}=\dfrac{1}{a^n}\to a^{-1}=\dfrac{1}{a}\\\\=\sqrt5\cdot\dfrac{1}{x^2}\cdot\dfrac{1}{y}=\dfrac{\sqrt5}{x^2y}$

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3 years ago

A piece of cloth is 6 1/4 meters long. If the cloth is cut into 1/2 meter long pieces, how many pieces can be made?

Greeley [361]

Answer:

Step-by-step explanation:

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3 years ago

Jared earns $455.00 per week as manager of the Save-Mart. What will be his income over 12 weeks

telo118 [61]

Heya, here is your Answer :-

Jared earns $455.00 / week .

So,

In the period of 12 weeks, he would be earning :

455*12 = $5,460

So, he would be earning <em>$5,460 anually.</em>

If you got some help from it, then pls, mark it the The <em>Brainliest...</em>

5 0

3 years ago

Plzzzz helpppp asapppppp **will mark brainliest **

Plzzzz helpppp asapppppp will mark brainliest