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3 years ago

13

Given the figure, what is tan(B)?

1 answer:

alexandr402 [8]3 years ago

6 0

$\tan B = \frac{b}{a}$

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The number of text messsages that teenagers send per month is normally

ki77a [65]

Answer:

$z=\frac{4415-3400}{450}=2.26$

And the explanation of this number is:"The number of text messages for Kendra it's 2.26 deviations above the mean"

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Calculate the z score

Let X the random variable that represent the number of text messages per month, and for this case we know the distribution for X is given by:

$X \sim N(3400,450)$

Where $\mu=3400$ and $\sigma=450$

And the best way to solve this problem is using the normal standard distribution and the z score given by:

$z=\frac{x-\mu}{\sigma}$

If we apply this formula to our probability we got this:

$z=\frac{4415-3400}{450}=2.26$

And the explanation of this number is:"The number of text messages for Kendra it's 2.26 deviations above the mean"

6 0

3 years ago

Me. Adams divides 223 markers equally among the 26 students in his class. He puts the extra markers in a box. What is the least

Soloha48 [4]

He puts 15 markers in the box. Hope this helps.

6 0

3 years ago

Scientists have discovered a vaccine for a debilitating disease. This year there were 570,000 reported new cases of the disease

Ket [755]

Answer: There are approximately 853827 new cases in 6 years.

Step-by-step explanation:

Since we have given that

Initial population = 570000

Rate at which population decreases is given by

$\frac{2}{3}$

Now,

First year =570000

Second year is given by

$570000\times (\frac{1}{3})$

Third year is given by

$570000(\frac{1}{3})^2$

so, there is common ratio ,

it becomes geometric progression, as there is exponential decline.

so,

$570000,570000\times \frac{1}{3},570000\times( \frac{1}{3})^2,......,570000\times (\frac{1}{3})^6$

a=570000

common ratio is given by

$r=\frac{a_2}{a_1}=\frac{1}{3}$

number of terms = 6

Sum of terms will be given by

$S_n=\frac{a(1-r^n)}{(1-r)}$

We'll put this value in this formula,

$S_6=\frac{570000(1-(\frac{1}{3})^6}{(1-\frac{1}{3})}\\\\=853827.16$

So, there are approximately 853827 new cases in 6 years.

6 0

2 years ago

PLEASE HELP For the expression below, write two other equivalent expressions using different terms. Make sure one is fully simpl

Julli [10]

Given:

The given expression is

$-4(x+2)-2x+4$

To find:

The two other equivalent expressions.

Solution:

We have,

$-4(x+2)-2x+4$

Using distributive property, we get

$=-4(x)-4(2)-2x+4$

$=-4x-8-2x+4$

So, one equivalent expression is $-4x-8-2x+4$ .

On further simplification, we get

$=(-4x-2x)+(-8+4)$

$=6x-4$

Therefore, the second and fully simplified equivalent expression is $6x-4$ .

5 0

3 years ago

Plz need help fast will mark the brainiest

prohojiy [21]

Answer:

0.0081

Step-by-step explanation:

yes bye that's the answer

8 0

3 years ago

Read 2 more answers