Answer:
The product is positive, thus it is 
Step-by-step explanation:
The full question in proper notation is:
"Find the product. If the result is negative, enter "-". If the result is positive, enter "+".
"
We have to work with it using Order of operations know as well as PEMDAS, thus expression inside parenthesis go first and exponents.
On this expression we have to work with exponents
Thus we get
Lastly we can work with multiplication and remembering that the multiplication of two negative signs becomes positive.
So the final simplified expression is 
The distance should be .625 of an inch. You get this by diving 11.25 by 18.
The number π is a mathematical constant, the ratio of a circle's circumference to its diameter, commonly approximated as 3.14159. It has been represented by the Greek letter "π" since the mid-18th century, though it is also sometimes spelled out as "pi" (/paɪ/
Answer:
2. 5 miles
Step-by-step explanation:
Given that:
Rental cost = $30
Cost per mile driven = 18 cent
Daily budget = $75
Greatest distance you can drive each day while staying within budget :
Rental cost + (cost per mile driven * distance) ≤ daily budget
$30 + 18d ≤ $75
18d ≤ 75 - 30
18d ≤ 45
d ≤ 45 / 18
d ≤ 2.5
Greatest distance you can drive each day while staying within budget is 2.5 miles.
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
