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Bas_tet [7]
3 years ago
6

Please help !!!!!!!!!!!

Mathematics
1 answer:
DochEvi [55]3 years ago
4 0
Forgive if I'm wrong but I think the answer is D).5.
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Restless Leg Syndrome and Fibromyalgia
Anna11 [10]

Answer:

The probability that a person with restless leg syndrome has fibromyalgia is 0.183.

Step-by-step explanation:

Denote the events as follows:

<em>F</em> = a person with fibromyalgia

<em>R</em> = a person having restless leg syndrome

The information provided is as follows:

P (R | F) = 0.33

P (R | F') = 0.03

P (F) = 0.02

Consider the tree diagram attached below.

Compute the probability that a person with restless leg syndrome has fibromyalgia as follows:

P(F|R)=\frac{P(R|F)P(F)}{P(R|F)P(F)+P(R|F')P(F')}

            =\frac{(0.33\times 0.02)}{(0.33\times 0.02)+(0.03\times 0.98)}\\\\=\frac{0.0066}{0.0066+0.0294}\\\\=0.183333\\\\\approx 0.183

Thus, the probability that a person with restless leg syndrome has fibromyalgia is 0.183.

3 0
3 years ago
How do I solve this?
bogdanovich [222]

Answer:

<h2>5(x + 7)²</h2>

Step-by-step explanation:

5(x+7)^4=\boxed5\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\cdot(x+7)\cdot(x+7)\\\\35(x+7)^2=\boxed5\cdot7\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\\\\15(x+7)^3=\boxed5\cdot3\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\cdot(x+7)\\\\GCF\bigg(5(x+7)^4,\ 35(x+t)^2,\ 15(x+7)^3\bigg)=\boxed5\cdot\boxed{(x+7)}\cdot\boxed{(x+7)}\\\\=5(x+7)^2

5 0
3 years ago
What is the domain of y=log(x+2)
Andru [333]

Answer:

\huge\boxed{x>-2\to x\in(-2;\ \infty)}

Step-by-step explanation:

y=\log(x+2)\\\\\bold{Domain:}\\\\x+2>0\qquad|\text{subtract 2 from both sides}\\\\x+2-2>0-2\\\\x>-2

8 0
3 years ago
Can someone please help me with geometry? Thank you.
aivan3 [116]

Answer:

X=10

Step-by-step explanation:

explanation is in the image above

hope this helps please mark me brainiest

7 0
2 years ago
What is the elimination to this solution i think its b
Blababa [14]

EXPLANATION:

To get the solution of the simultaneous equation, using the elimination method:

We will have the following steps:

Step 1:

Write the two equations:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{7}{2}x-3 \end{gathered}

Step2: Subtract the two equations:

\begin{gathered} y-y=-\frac{1}{2}x-(-\frac{7}{2}x)+3-(-3) \\ 0=-\frac{1}{2}x+\frac{7}{2}x+6 \\  \end{gathered}

Step 3: Simplify the expression

\begin{gathered} 0=3x+6 \\ 3x=-6 \\ x=-\frac{6}{3} \\ x=-2 \end{gathered}

Step 4: Substitute x=-2 into the formula:

\begin{gathered} y=-\frac{1}{2}x+3 \\ y=-\frac{1}{2}\times-2+3 \\ y=1+3 \\ y=4 \end{gathered}

Therefore, the answer is

(-2,4)

Thus,

Option B is correct

5 0
1 year ago
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