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lilavasa [31]
3 years ago
10

Help me solve the following​

Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0

Answer:

wow so difficult omg heheeh

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Evaluate the function rule to find the range of each function for the domain {-3, 0, 5}. f(x) = x² − 6x + 4
harina [27]
Range is output for given input

domain is D={-3,0,5}
input -3,0 and 5 for x

f(-3)=(-3)^2-6(-3)+4
f(-3)=9+18+4
f(-3)=31

F(0)=(0)^2-6(0)+4

f(0)=0-0+4

f(0)=4


f(5)=(5)^2-6(5)+4

f(5)=25-30+4

f(5)=-1


Domain={-3,0,5}

Range={31,4,-1}



5 0
3 years ago
Is a 118 supplementary or complementary?pls ASAP!!
Alchen [17]

Answer:

\huge\boxed{Supplementary \ Angle}

Step-by-step explanation:

118 is a supplementary angle. It is not a complementary angle because complementary angles add up to 90 and 118 is greater than 90 degrees. So, 118 is a supplementary angle and it is an angle adding up to 180 degrees with any other angle measuring 62 degrees.

4 0
3 years ago
Read 2 more answers
Help me ASAP I don't know how to do it and this is homework
Rus_ich [418]
56 pages/4 hours = 126 pages/x pages
Then you cross multiply
56*x =4*126 ---> 56x=504
Then you divide 56 to both sides
56x/56=504/56
The 56 cancels on the left side and then you get
x=9

So your proportion are:
56 pages/4hours=126 pages/9 hours
8 0
3 years ago
If l is a line whose equation is y=5x-3, find the equation of the image of l under each of the following translations a. (x,y) -
Naddika [18.5K]
Consider the line y=5x-3. Two solutions (x, y) of this equation, are points on the line.

For example, let x=0, then y=-3. So (0, -3) is a point on the line.

If x=1, then y=5*1-3=5-3=2, so (1, 2) is a point on the line.

a) 

Consider the transformations of these two points under <span>(x,y) --> (x, y-6):

</span>(0,-3) --> (0, -3-6)=(0, -9),
(1, 2) --> (1, 2-6)=(1, -4).

So (0, -3) and (1, 2) are translated to respectively (0, -9) and (1, -4).

The whole line is translated to the line containing (0, -9) and (1, -4).

The slope of the new line is m= \frac{-9-(-4)}{0-1}= \frac{-5}{-1}=5. The equation of the line is:

                                   y-(-9)=5(x-0), 

that is,                               y=5x-9.


b) 

Consider the transformations of these two points under (x,y) --> (x+2, y):

(0,-3) --> (0+2, -3)=(2, -3),
(1, 2) --> (1+2, 2)=(3, 2).

The slope of the new line is m= \frac{-3-2}{2-3}= \frac{-5}{-1}=5.

The equation of the line is
                 
                                   y-2=5(x-3), 
which can be written as
                                        y=5x-13.


Answer:

a)  y=5x-9

b)  y=5x-13


4 0
3 years ago
What is the product of -2/5 * (-11/12) in simplest form.
Leya [2.2K]

Answer:

the answer is 11/30

Step-by-step explanation:

when you do the original equation it on 22/60 and that simplified is 11/30

4 0
3 years ago
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