All categories

1 year ago

Please help thank you!!!!

Mathematics

1 answer:

WINSTONCH [101]1 year ago

8 0

Answer:

first option;

x-int: -5, 1

y-int: -1

Step-by-step explanation:

x-int: describes where the function touches the x-axis (left to right). This function touches the points (0,-5) and (0,1).

y-int: describes where the function touches the y-axis (up and down). This function touches the point (0,-1).

You might be interested in

Solve these linear equations in the form y=yn+yp with yn=y(0)e^at.

WINSTONCH [101]

Answer:

a) $y(t) = y_{0}e^{4t} + 2$ . It does not have a steady state

b) $y(t) = y_{0}e^{-4t} + 2$ . It has a steady state.

Step-by-step explanation:

a) $y' -4y = -8$

The first step is finding $y_{n}(t)$ . So:

$y' - 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r - 4 = 0$

$r = 4$

So:

$y_{n}(t) = y_{0}e^{4t}$

Since this differential equation has a positive eigenvalue, it does not have a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' -4(y_{p}) = -8$

$(C)' - 4C = -8$

C is a constant, so (C)' = 0.

$-4C = -8$

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{4t} + 2$

b) $y' +4y = 8$

The first step is finding $y_{n}(t)$ . So:

$y' + 4y = 0$

We have to find the eigenvalues of this differential equation, which are the roots of this equation:

$r + 4 =$

$r = -4$

So:

$y_{n}(t) = y_{0}e^{-4t}$

Since this differential equation does not have a positive eigenvalue, it has a steady state.

Now as for the particular solution.

Since the differential equation is equaled to a constant, the particular solution is going to have the following format:

$y_{p}(t) = C$

$(y_{p})' +4(y_{p}) = 8$

$(C)' + 4C = 8$

C is a constant, so (C)' = 0.

$4C = 8$

$C = 2$

The solution in the form is

$y(t) = y_{n}(t) + y_{p}(t)$

$y(t) = y_{0}e^{-4t} + 2$

6 0

3 years ago

A pilot was scheduled to depart at 4:00 pm, but due to air traffic, her departure has been delayed by 15 minutes. Air traffic co

Sladkaya [172]

Answer:

y = (1/2)x + 15

Step-by-step explanation:

First, we need to identify the parts of the problem that we already know:

1) The pilot was originally scheduled to depart at 1600 (4:00 pm).

2) The pilot's departure was delayed by 15 minutes.

3) the traffic control approved a new flight plan that would allow the pilot to travel to her destination two times faster than her original flight plan.

For the problem's sake, let us pretend that the pilot's original flight plan was going to take two hours. Had he/she left at 4:00 pm, the pilot would have landed at 6:00 pm.

With a delay of 15 minutes, the duration of the flight would still remain constant, so the pilot would arrive at their destination two hours later, at 6:15 pm.

With the new flight plan, the pilot's travel time would be cut in half, so it would be 1/2 of x (time, in minutes, of original flight). Thus, her new flight time would only be one hour (60 minutes).

So, now we have to subtract 1/2 from the original flight time, as well as adding the 15 minute delay for departure. Now we can create a formula:

y = (1/2)x + 15

Y equals the total amount of time (in minutes) that it would take for the plane to leave. We divide x (total time of original flight) by 2, because her new flight plan will be twice as fast. Then we have to take into account the extra 15 minute delay!

8 0

3 years ago

Lincoln is measuring the angles of quadrilateral WXYZ to determine whether it is congruent to the quadrilateral below.

suter [353]

M∠X = 140 degrees and m∠Y = 94 degrees

4 0

3 years ago

How many solutions are there 2x - y = 1 - 4x + y = 1

Bezzdna [24]

infinitely many solutions

8 0

3 years ago

Read 2 more answers

Luis has $550 saved for a car,and he saves an additional $50 per week. Kya has 810 saved for a trip, and she saves an additional

Debora [2.8K]

About 9 weeks. With Luis at 1000 and kya At 1008. Theirs no exact.

Graph into calc
Stat plot
Y1= 550+50x
Y2= 810+22x
X representing the weeks

Then press 2nd and graph.

4 0

3 years ago