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3 years ago

What is the range of f?

Mathematics

1 answer:

Zielflug [23.3K]3 years ago

8 0

Answer:

The range of f(x) is (−∞,∞), which is all real numbers. In fact, this range holds for any base for the log. 3. For 0">a>0 and a≠1, f(x)=ax has a range of (0,∞).

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Find a solution to the system. Make sure to write as a coordinate.

RUDIKE [14]

Answer:

x=2, y=3

Step-by-step explanation:

This is a system of equations.

To solve a system of equations, we use the substitution method.

We can plug in the first equation, $x=2y-4$ , into the value for x in the second equation. Now, the second equation looks like this:

$2*(2y-4)+y=7$

We simplify and solve for y:

→ $4y-8+y=7$

→ $5y=15$

→ $y=3$

Now, we plug in the value for y, which is 3, into either equation. I will just use the first equation:

→ $x=2*3-4$

→ $x = 2$

Let me know if my explanation is unclear.

3 0

3 years ago

Jonathan saved money to have a party if he spends to eight of his money on food 1/5 of his money on prices and two tenths of his

erik [133]

Answer:

7/20 is left

Step-by-step explanation:

2/8 (reduced is 1/4) for food

1/5 for prizes

2/10 (reduced is 1/5) for decorations

? for what's left

Add all the fractions up by finding a common denominator.

1/4 + 1/5 + 1/5

5/20 + 4/20 +4/20 = 13/20

He spent 13/20 of his money on this stuff. What part of that is left?

1 - 13/20 (AKA 20/20 - 13/20)

= 7/20

8 0

3 years ago

4x+7y=19 Y=x+9 U must solve it in substitution method

Hunter-Best [27]

The answer is (-4, 5) x= -4 y= 5

8 0

3 years ago

Evaluate the line integral for x^2yds where c is the top hal fo the circle x62 _y^2 = 9

natulia [17]

Parameterize $C$ by

$\mathbf r(t)=\langle x(t),y(t)\rangle=\langle3\cos t,3\sin t\rangle$

where $0\le t\le\pi$ . Then the line integral is

$\displaystyle\int_Cx^2y\,\mathrm dS=\int_{t=0}^{t=\pi}x(t)^2y(t)\left\|\frac{\mathrm d\mathbf r(t)}{\mathrm dt}\right\|\,\mathrm dt$
$=\displaystyle\int_{t=0}^{t=\pi}(3\cos t)^2(3\sin t)\sqrt{(-3\sin t)^2+(3\cos t)^2}\,\mathrm dt$
$=\displaystyle3^4\int_{t=0}^{t=\pi}\cos^2t\sin t\,\mathrm dt$

Take $u=\cos t$ , then

$=\displaystyle-3^4\int_{u=1}^{u=-1}u^2\,\mathrm du$
$=\displaystyle3^4\int_{u=-1}^{u=1}u^2\,\mathrm du$
$=\displaystyle2\times3^4\int_{u=0}^{u=1}u^2\,\mathrm du$
$=54$

6 0

3 years ago

PLEASE HELP WILL MARK BRAINLIEST

KIM [24]

Answer:

4th dot

Step-by-step explanation:

hope this helps

4 0

3 years ago

Read 2 more answers