Answer:
Step-by-step explanation:
This is a binomial probability distribution because there are only 2 possible outcomes. It is either a randomly selected student grabs a packet before being seated or the student sits first before grabbing a packet. The probability of success, p in this scenario would be that a randomly selected student sits first before grabbing a packet. Therefore,
p = 1 - 0.81 = 0.91
n = 9 students
x = number of success = 3
The probability that exactly two students sit first before grabbing a packet, P(x = 2) would be determined from the binomial probability distribution calculator. Therefore,
P(x = 2) = 0.297
a= 34 degrees
b= 28 degrees
c= 62 degrees
Step-by-step explanation:
First you know that b is 1/2 of 56 degrees or 28.
The triangle with the a in it is isoceles because the two sides are both radii.
In the triangle the top angle = 112 because it is a centeral angle to the 112 arc.
Angle a and opposite to a are equal and then have to be 34 degrees to equal 180.
We know two arc lengths are 112 and 56 and the one with angle a has to be 34x2 or 68.
a whole circle equals 360.
360-56-68-112 = 124
Angle c = 1/2 of 124, or 62 degrees
X(x+1) 1(x+4)
x^2+x+x+4
x^2+2x+4
P of selecting point on the shaded region = shaded area/whole area
<span>P( selecting point on the shaded ) = ( the four shaded circles ) / the whole square </span>
<span>P of selecting point on the shaded = ( 4 * ( π * r^2 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( 4 * ( π * (x/4)^2 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( 4 * ( π * x^2/16 ) )/ x^2 </span>
<span>P of selecting point on the shaded = ( π * x^2/4 )/ x^2 </span>
<span>P of selecting point on the shaded = x^2( π/4 )/ x^2 </span>
<span>P( selecting point on the shaded ) = π/4 ≈ 0.7854 ≈ 79%
=80%
D is right option hope this helps</span>
5 different amount
3d 2n 1q=65cents
1d 1n 1q=40cents
2d 2n 1q=55cents
1d 2n 1g=45cents
3d 1n 1q=60cents
