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emmasim [6.3K]
2 years ago
7

Solve the equation. Show all work. -2 (4 - x) = 12x – 3 (I think this is 9th grade algebra)

Mathematics
2 answers:
Nady [450]2 years ago
8 0

Answer:

x = -1/2 or -0.5

Step-by-step explanation:

-2 (4 - x) = 12x - 3

Distribute the -2

-8 + 2x = 12x -3

Add 3 to both sides

-5 + 2x = 12x

Subtract 2x from both sides

-5 = 10x

Divide both sides by 10

x = -1/2 or -0.5

Genrish500 [490]2 years ago
4 0

Answer:

-1/2

Step-by-step explanation:

-2 (4 - x) = 12x – 3

-8+2x=12x-3

+8            +8

2x=12x+5

-12x  -12x

-10x=5

/-10  /-10

= -1/2

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1. A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts o
Sauron [17]

Answer:

The confidence interval estimate of the population mean is :

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The correct option is (A).

Step-by-step explanation:

The amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city are:

S = {0.58, 0.82, 0.10, 0.98, 1.27, 0.56, 0.96}

A (100-\alpha )\% confidence interval for the population mean (μ) is an interval estimate of the true value of the mean. This interval has a (100-\alpha )\% probability of consisting the true value of mean.

⇒ Since the population standard deviation is not provided we will use the <em>t</em>-distribution to construct the 99% confidence interval for mean.

⇒ The formula for confidence interval for the population mean is:

                                          \bar x\pm t_{\alpha/2,(n-1)}\times \frac{s}{\sqrt{n}}

Here,

\bar x = sample mean

<em>s </em>= sample standard deviation

<em>n</em> = sample size

t_{\alpha/2,(n-1)} = critical value.

The degrees of freedom for the critical value is, (<em>n</em> - 1) = 7 - 1 = 6.

The significance level is: \alpha =1-Confidence\ level=1-0.99=0.01

The critical value is:

t_{\alpha/2,(n-1)}=t_{0.01/2, 7}=t_{0.05,7}=3.143

**Use the <em>t</em>-table for the critical value.

Compute the sample mean and sample standard deviation as follows:

\bar x=\frac{1}{7}(0.58+ 0.82+ 0.10+ 0.98+ 1.27+ 0.56+ 0.96) =0.753

\int\limits^a_b {x} \, dx s=\sqrt{\frac{\sum (x{i}-\bar x)^{2}}{n-1} } =\sqrt{\frac{1}{6} \times 0.859743} =0.379

The 99% confidence interval for μ is:

x^{2} CI=0.753\pm 3.143\times\frac{0.379}{\sqrt{7}} \\=0.753\pm0.143\\=(0.61, 0.896)\\\approx(0.61, 0.90)

The confidence interval estimate of the population mean is:

(0.61 ppm, 0.90 ppm)

The upper and lower limit of the 99% confidence interval indicates that the true mean value is less than 1 ppm. This implies that there is not too much mercury in tuna sushi

Because it is possible that the mean is not greater than 1 ppm. Also, at least one of the sample values is less than 1 ppm, so at least some of the fish are safe.

Thus, the correct option is (A).

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Answer

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