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NemiM [27]
3 years ago
15

deep. Calculate its volume (in cm in terms of m). [JAMB] 500 A right pyramid on a base 10 m square is 15 m high. a Find the volu

me of the pyramid. b If the top 6 m of the pyramid are removed, what is the volume of the remaining frustum?​
Mathematics
2 answers:
Reptile [31]3 years ago
7 0

Answer:

below

Step-by-step explanation:

that is the procedure above

s344n2d4d5 [400]3 years ago
6 0

9514 1404 393

Answer:

  a. 500 m³

  b. 468 m³

Step-by-step explanation:

<u>Given</u>:

  a square base pyramid with side 10 m and height 15 m

<u>Find</u>:

  a) the volume of the pyramid

  b) the volume of the remaining frustum with the top 6 m removed

<u>Solution</u>:

a) The volume of the pyramid is given by the formula ...

  V = 1/3Bh

where B = s², the area of the square base, and h is the height

  V = (1/3)(10 m)²(15 m) = 500 m³

The volume of the pyramid is 500 m³.

__

b) The top 6 meters constitute a similar pyramid with a scale factor of 6/15 = 2/5. The volume of that portion is then the total volume multiplied by the cube of the scale factor:

  volume of top 6 feet = (500 m³)(2/5)³ = 32 m³

Then the volume of the remaining frustum is ...

  500 m³ -32 m³ = 468 m³

The volume of the remaining frustum is 468 m³.

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3 times

Step-by-step explanation:

heaviest : 9/10 kg.. 0.9kg

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Zinaida [17]

Answer:

  1. Parallel
  2. Neither parallel nor perpendicular ​
  3. Perpendicular

Step-by-step explanation:

<u>Given line m:</u>

  • y = 4/5x - 3

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1.<u> y = 4/5x + 3</u>

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2. <u>y = -4/5x + 3</u>

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2 years ago
Find the area of the regular trapezoid. The figure is not drawn to scale. The top side is 4, the bottom side is 7, and both side
svp [43]
A regular trapezoid is shown in the picture attached.

We know that:
DC = minor base = 4
AB = major base = 7
AD = BC = lateral sides or legs = 5

Since the two legs have the same length, the trapezoid is isosceles and we can calculate AH by the formula:

AH = (AB - DC) ÷ 2
      = (7 - 5) ÷ 2
      = 2 ÷ 2
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Now, we can apply the Pythagorean theorem in order to calculate DH:
DH = √(AD² - AH²) 
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      = √(25 - 1)
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      = 2√6

Last, we have all the information needed in order to calculate the area by the formula:

A =  \frac{(AB + CD)DH}{2}

A = (7 + 5) × 2√6 ÷ 2
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The area of the regular trapezoid is 12√6 square units.

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yan [13]
FIRST. find the factors:
X=-5 --> (X + 5) = 0
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