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3 years ago

Can I get some help with this just tell me where they go lol thanks

Mathematics

1 answer:

jeka943 years ago

8 0

Hope this helps! the colors of the highlight match where the things go.

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How do you write a improper fraction a mixed number if it's a negative

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You simply do it the same way as a positive number, just with a negative sign in front :)

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3 years ago

A movie collector has 105 movie posters and 90 band posters if she sells 21 movie posters then how many band posters should she

kotykmax [81]

Hi there! :)

Answer:

In order to maintain the same ratio, she should sell 18 band posters.

Step-by-step explanation:

Initial ratio:

Ratio is: 105 movie posters for 90 band posters = 105 : 90

She sells 21 movie posters, which means that we are left with 105 movies minus the 21 she sold.

105 - 21 = 84 → She now has 84 movie posters.

In order to answer your question, you'll need to use the cross product method:

105 movie posters → 90 band posters

84 movie posters → X

(90 × 84) ÷ 105 = X

7,560 ÷ 105 = X

72 = X ⇒ Number of band posters she should have left to maintain the same ratio.

She has 90 band posters :

90 - X = 72

Add "X" to each side of the equation → 72 + X = 72 + X

90 = 72 + X

Subtract 72 from each side of the equation → 90 - 72 = 18

18 = X

There you go! I really hope this helped, if there's anything just let me know! :)

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3 years ago

What is the answer to this 2√3-5√÷√3+2√5

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Answer:

$\sqrt{ \div 3}$

mathematicallly error sentence!

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The researcher has limited resources. He sends 9 emails from a Latino name, and 14 emails from a non-Latino name. For the Latino

deff fn [24]

Answer: 38.41 minutes

Step-by-step explanation:

The standard error for the difference in means is given by :-

$SE.=\sqrt{\dfrac{\sigma_1^2}{n_1}+\dfrac{\sigma^2_2}{n_2}}$

where , $\sigma_1$ = Standard deviation for sample 1.

$n_1$ = Size of sample 1.

$\sigma_2$ = Standard deviation for sample 2.

$n_2$ = Size of sample 2.

Let the sample of Latino name is first and non -Latino is second.

As per given , we have

$\sigma_1=82$

$n_1=9$

$\sigma_2=101$

$n_2=14$

The standard error for the difference in means will be :

$SE.=\sqrt{\dfrac{(82)^2}{9}+\dfrac{(101)^2}{14}}$

$SE.=\sqrt{\dfrac{6724}{9}+\dfrac{10201}{14}}$

$SE.=\sqrt{747.111111111+728.642857143}$

$SE.=\sqrt{1475.75396825}=38.4155433158\approx38.41$

Hence, the standard error for the difference in means =38.41 minutes

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What is true about personal financial planning?

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C. Your financial goals will change over time.

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