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1 answer:
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Answer:
C
Step-by-step explanation:
Given:
Number of samples, n = 100
let number of sample that favoured candidate A be x = 80
probability, p' = x/n = 80/100 = 0.8
probability, p for significance = 75% = 0.75
Using Z-proportion test statistics, we have
Z =
Substituting the values, we have
Z =
Z = 0.05 / 0.0433 = 1.1547
The p-value is
P(Z>1.1547) = 1 - P(Z≤1.1547)
Checking the Z-score table, P(Z≤1.1547) = 0.8789
Hence, we have 1 - 0.8789
= 0.1241
Hence, the p-value is greater than 0.05, so we cannot say it is very significant.
Hence, the population in favour of candidate A is not significantly greater than 75%
Answer:
Consider the complete question is,
Dana buys dress shirts from a clothing manufacturer for s dollars each, and then sells the dress in her retail clothing store at a 35% markup
a. Write the markup as a decimal
b. write an expression for the retail price
c. What is the retail price of a dress shirt that Dana purchased for 32.00
d. How much was added to the original price of the dress shirt?
Reference : brainly.com/question/2202598
Solution :
Here, s represents the price of each dress shirt,
a. Since, markup percentage = 35%,
Thus, the markup in each shirt = 35% of price of each dress shirt
= 35% of s
= 0.35s
b. Retail price = original price + markup
= s + 0.35s
= 1.35s
c. if s = 32,
Retail price = 1.35(32) = 43.2
d. The added amount in original price = Retail price - original price
= 43.2 - 32
= 11.2