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Hoochie [10]
3 years ago
8

What is the closed linear form for this sequence given a1 = 13 and an + 1 = an + 4?

Mathematics
1 answer:
Oduvanchick [21]3 years ago
3 0
A1=13 and a+1 = an+4 

13+1=13n+4
14=17n
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8_murik_8 [283]
P = k/V

84 = k/51
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P = 4,284 / 153
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Lesechka [4]

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Round. each to the nearest tenth 10,061
lora16 [44]
10,060 would be the answer.
3 0
3 years ago
<img src="https://tex.z-dn.net/?f=x%5Ea%3Dy%5Eb%3Dz%5Ec%20%5C%5Cxyz%3D1%5C%5Cab%2Bbc%2Bca%3D%3F" id="TexFormula1" title="x^a=y^b
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Answer:

<em>ab+bc+ca=0</em>

Step-by-step explanation:

We are given:

x^a=y^b=z^c

xyz=1

Separating equations:

x^a=z^c

y^b=z^c

Solving the first equation for x:

\displaystyle x=z^\frac{c}{a}

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\displaystyle y=z^\frac{c}{b}

Substituting in

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\displaystyle z^\frac{c}{a}z^\frac{c}{b}z=1

Adding the exponents:

\displaystyle z^{\frac{c}{a}+\frac{c}{b}+1}=1

Since 1=z^0:

\displaystyle z^{\frac{c}{a}+\frac{c}{b}+1}=z^0

The base is z on both sides so we get rid of them:

\displaystyle \frac{c}{a}+\frac{c}{b}+1=0

Multiplying by ab:

bc+ac+ab=0

Reordering:

ab+bc+ca=0

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3 years ago
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UNO [17]

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Step-by-step explanation:

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  2. Increase means add: 110 + 11 = 121
8 0
4 years ago
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