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ch4aika [34]
3 years ago
10

suppose you scored a 99%, 67%, 83%, and 86% on your last four science tests. if your next text counts twice, is it possible to a

verage a 90%? explain your answer.
Mathematics
1 answer:
Irina18 [472]3 years ago
6 0

Answer:

If you get the maximum grade in the last test, your average grade will still be below 0.9 = 90%, which means that it is not possible to average a 90%.

Step-by-step explanation:

Average grade:

The average grade is given by the sum of all averages, divided by the number of tests.

In this question:

99%, 67%, 83%, and 86%.

Next test counts twice, which means that in total, there are 6 tests.

Is it possible to average a 90%?

The maximum grade in a test is 100% = 1. I will calculate the average grade you get a 100% on the last test, which is worth 2. So

M = \frac{0.99+0.67+0.83+0.86+2*1}{6} = \frac{5.35}{6} = 0.892

If you get the maximum grade in the last test, your average grade will still be below 0.9 = 90%, which means that it is not possible to average a 90%.

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Which number sentence is true?
Artemon [7]

Answer:

yes

Step-by-step explanation:

but really nice to the world I'm happy for you because you is so buetiful

5 0
2 years ago
2 numbers are in the ratio 1:2 if the first number is decreased by 5 and second number is increased by 4 their ratio becomes 5:4
Anna35 [415]

Answer:

-20/3 & -40/3

Step-by-step explanation:

Let’s say that the 1st number is X and the 2nd number is Y.

Given that x:y = 1:2 => x/y = 1/2 => 2x = y

and a-5/y+4 = 5/4 (The first number is decreased by 5 and the second number is increased by 4.)

=> 4(x - 5) = 5 (y + 4)

=> 4x - 20 = 5y + 20

=> 4x - 5y = 40

As, 2x = y , 4x = 2y

=> 2y - 5y = 40

=> -3y = 40

=> y = -40/3 ; x = y/2 = -20/3

This might be confusing but I hope this helps :)

7 0
3 years ago
Three hundred and eighty -two tenthousandths
AlladinOne [14]

Answer:

382000

Step-by-step explanation:

8 0
3 years ago
There are ​$528 available to fence in a rectangular garden. The fencing for the side of the garden facing the road costs ​$9 per
andrew-mc [135]

Answer:

  22 ft by 44 ft, with 22 ft parallel to the road

Step-by-step explanation:

Problems in optimizing rectangular area for a given perimeter or perimeter cost all have a similar solution: the length (or cost) of one pair of opposite sides is equal to that of the other pair of opposite sides.

Here, that means that the sides perpendicular to the road will have a total cost of $528/2 = $264, so will have a total length of $264/($3/ft) = 88 ft. Since it is a rectangle, the dimension perpendicular to the road is 44 ft.

Likewise, the sides parallel to the road will have a total cost of $264. If x is the length in that direction, this means ...

  9x +3x = 264

  12x = 264

  264/12 = x = 22

The length of the garden parallel to the road is 22 ft.

_____

If you solve this directly, you get the same result. Let x be the distance parallel to the road. Then the cost of fence for the two sides parallel to the road is (3x +9x) = 12x.

The length of fence perpendicular to the road will use the remaining cost, so that length will be (528 -12x)/(2·3). (Half of the remaining fence is used on each of the two parallel sides.) This expression for length simplifies to (88-2x).

Then the area of the garden will be the product of its length and width:

  area = x(88 -2x)

This is the equation for a downward-opening parabola with zeros at x=0 and x=44. The vertex is located halfway between those zeros, at x = 22.

The dimensions of the largest garden are 22 ft parallel to the road and 44 ft perpendicular to the road.

8 0
2 years ago
Given points A (-8,7) and B (6, -9), find the midpoint, M
Vladimir [108]

Hey there! I'm happy to help!

To find the x value of the midpoint, you add the 2 x values and divide by 2.

-8+6=-2

-2/2=-1

For the y value, you do the same thing but with the y values.

7-9=-2

-2/2=-1

Therefore, our midpoint is (-1,-1).

Have a wonderful day! :D

7 0
3 years ago
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