Which represents the domain of the relation {(–1, 4), (2, –3), (0, –2), (1, –3)}?

1 answer:

7 0

Domain means the “input” which is like when u input a number in a vending machine and then the output is you getting the chips or whatever u got from imputing the number. So the answer would be C because is is asking for the front numbers in the relation or plots of points.

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The coordinates of the vertices of quadrilateral ABCD are A(-5, 1), B(-2,5), C(5, 3),

sladkih [1.3K]

Step-by-step explanation:

To calculate a slope, we need to apply: $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

Applying formula to each slope:

$m_{AB}=\frac{5-1}{-2-(-5)} = \frac{4}{3} \\m_{BC}=\frac{3-5}{5-(-2)} =\frac{-2}{7}\\m_{CD}=\frac{-1-3}{2-5}=\frac{-4}{-3} =\frac{4}{3}$

So, as you can see, there are equal pair of slopes, meaning that they are parallels, which<em> demonstrate that it's actually a quadrilateral figure.</em>

6 0

3 years ago

Read 2 more answers

Determine if the columns of the matrix form a linearly independent set. Justify your answer. Choose the correct answer below. A.

kondaur [170]

Th matrix is missing. The matrix is :

$\begin{bmatrix}1 &-4 &4 \\ -4 &16 & 4 \end{bmatrix}$

Solution :

The column of the matrix are $\begin{bmatrix}1\\ -4\end{bmatrix}$ , $\begin{bmatrix}-4\\ 16\end{bmatrix}$ , $\begin{bmatrix}4\\ 4\end{bmatrix}$

Now each of them are vectors in $IR^2$ . But $IR^2$ has dimensions of 2. But there are 3 column vectors, hence they are linearly dependent.

Therefore, the column of the given matrix does not form the $\text{linearly independent set}$ as the set contains $\text{more vectors}$ than there are entries in each vector.