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seraphim [82]
3 years ago
5

Could someone help with the questions in the images below? I found them difficult

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0
Question 1a - You have got this correct, the median mark is 35
Question 1b- To work out the range, you must do the largest value subtract the smallest value. For your data, this would be 57 - 13 = 44

Question 2 - You have drawn the lines in the correct places, but you have not used a ruler. In order to get full marks on a question like this you must use a ruler.

Question 3 - Your lower quartile and median is correct, to find the upper quartile, we do 3(n/4). 'n' is the number of data points - in this case 120.
120/4 = 30
30 x 3 = 90
Go across the graph at 90 to see when the line is hit.
From what I can tell, the Upper Quartile is 3.

Next just find the maximum value.
Again, by the looks of it, the Maximum value is 8.5.

Now you have all the data needed for the box plot.

Min = 0
LQ = 0.8
Med = 2.1
UQ =  3
Max = 8.5

Using this information, draw a box plot like you did on the previous question.
<em>Again, I must stress that any line that you draw (unless purposely curved) must be drawn with a ruler; even on the graph at the top, during you working out. If you do not use a ruler, marks can be lost/taken away.</em>

Question 4a - For the median on a cumulative frequency chart, you must find the halfway point in the data. For this, we do n/2. In this case, n = 40
40/2 = 20
Draw a line (using  ruler) across at 20 until you reach the line.
Draw another one down to help you read the number.
The median looks like 34 seconds.
Question 4b - For this question, we already know the Min, Med and Max. Now we must work out the LQ and UQ.

Remember, LQ = n/4
In this case, n = 40
40/4 = 10
Look across at ten and you will find that the LQ = 16 seconds

To work out the UQ, we multiply the LQ place by 3 3(n/4).
3 x 10 = 30
30 on the graph takes us up to 45 seconds.

We now know that the:
Min = 9
LQ = 16
Med = 34
UQ = 45
Max = 57

With this information, draw a box plot like you have in the previous questions.

Question 5 - Good things to always compare on box plots are the Min/Max/Range and the Inter Quartile Range.
The boys had a lowest minimum and a higher maximum, this means that their range is larger, resulting in a large spread of data in comparison to the girls.
The Inter Quartile Range is the difference between the Upper Quartile and the Lower Quartile (how wide the box is).
The boy IQR = 45 - 16 = 29
The girls IQR = 34 - 23 = 11
Again, the girls have much more concise results; even though they did not get the quickest result, they were more like one another.

Question 5a - The median in a box plot is always the line down the centre of the box. In this case:
Median = 24 marks
Question 5b - The IQR is always the UQ - LQ
With this data, the IQR is the following:
36 - 17 = 19 marks

Hope this helps
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If 90 percent of automobiles in Orange County have both headlights working, what is the probability that in a sample of eight au
Marta_Voda [28]

Answer:

P(X \geq 7) = P(X=7) +P(X=8)

And we can find the individual probabilities using the probability mass function

P(X=7)=(8C7)(0.9)^7 (1-0.9)^{8-7}=0.3826  

P(X=8)=(8C8)(0.9)^8 (1-0.9)^{8-8}=0.4305  

And replacing we got:

P(X \geq 7) = P(X=7) +P(X=8)=0.3826 +0.4305=0.8131

Step-by-step explanation:

Previous concepts  

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Solution to the problem

Let X the random variable of interest "number of automobiles with both headligths working", on this case we now that:  

X \sim Binom(n=8, p=0.9)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

And for this case we want to find this probability:

P(X \geq 7) = P(X=7) +P(X=8)

And we can find the individual probabilities using the probability mass function

P(X=7)=(8C7)(0.9)^7 (1-0.9)^{8-7}=0.3826  

P(X=8)=(8C8)(0.9)^8 (1-0.9)^{8-8}=0.4305  

And replacing we got:

P(X \geq 7) = P(X=7) +P(X=8)=0.3826 +0.4305=0.8131

7 0
3 years ago
Read 2 more answers
2. <br> Find the area of the region bounded by the graphs of y = -x2 + 3x + 4 and y = 4. (5 points)
Kipish [7]

Answer:

4.5 sq. units

Step-by-step explanation:

area = -⅓x³+3/2 x² ] 0 to 3

= -⅓(3)³+ 3/2 (3)² -0

= -9 + 27/2

= -9 + 13.5

= 4.5 sq. units

8 0
3 years ago
Evaluate 5+\left(-3\right)-65+(−3)−65, plus, left parenthesis, minus, 3, right parenthesis, minus, 6.
Serga [27]

The question is not well-expressed, but it looks like you want to evaluate

5 + (-3) - 65 + (-3) - 65 + (-3) - 6

Answer:

-140

Step-by-step explanation:

First of all, note the following

- Multiplying a negative number by another negative number gives a positive number.

- Multiplying a negative number by a positive number gives a negative number.

- Multiplying a positive number by a positive number gives a positive number.

- Brackets mean multiplication.

So

5 + (-3) - 65 + (-3) - 65 + (-3) - 6

= 5 - 3 - 65 - 3 - 65 - 3 - 6

= -140

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3 years ago
Which parent functions go through the origin? Select all that apply.
Dvinal [7]
It also goes from linear too, I don’t know what else sorry
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3 years ago
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The tennis club where you play tennis charges $50.00 per month and $10.00 per hour of court time. If your current month's bill i
anyanavicka [17]

Answer:

Option B. 5 hours

Step-by-step explanation:

The tennis club charges monthly fees = $50.00

and per hour charges of court time = $10.00

Lets assume you play number of hours in a month = x hr

So, per hour charges would be = $10x

Total payment = monthly charges + charges of played hours

$100.00 = $50.00 + 10x

10x = 100 - 50

10x = 50

x = 5

Option B. You used 5 hours court time.

7 0
3 years ago
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