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pickupchik [31]
3 years ago
13

How many feet are in 2 miles 300 feet?

Mathematics
1 answer:
Stells [14]3 years ago
3 0
I believe the answer would be 10,860 my friend :) good luck with your problem, and have a great day
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Solve the following equation <br> x-5.5=4
Brilliant_brown [7]
Solution: X=9.5

Explanation: x-5.5=4 —> x=4+5.5 —> x=9.5
3 0
3 years ago
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Kendra has $ 7.35 in nickels and quarters. If she has 15 more quarters than nickels, how many of each coin does she have?
lozanna [386]

x*5 - quarter amount

(x+15)*25- nickels amount

(x*5)+((x+15)*25)=735

5x+25x+375=735

30x=735-375

30x=360

x=360/30=12 - number of nickels

x+15=12+15=27 - number of quarters

CHECK

12*5=60 ¢

27*25=675 ¢

675+60=735 ¢ or $7.35

5 0
4 years ago
A shopkeeper has 10m cartons of eggs. There were 12 eggs in each carton. He sold 2 of the carton and use 1 carton to cook for hi
Nataly [62]

Given : Shopkeeper had 10m Cartons of Eggs

Given : He sold 2 of the Cartons and used 1 Carton to cook for his Family

⇒ Shopkeeper took 3 Cartons of Eggs form 10m Cartons of Eggs

⇒ The Shopkeeper is left with (10m - 3) Cartons of Eggs

Option (1) is the Answer

6 0
3 years ago
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Write the equation of the line described
Alexeev081 [22]

Step-by-step explanation:

slope = x factor = - 5/2

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

New slope = 2/5 = m

y = mx + b

from the point given y = 2 | x = -4

2 = (2/5 × -4 ) + b

2 = - 1.6 + b

b = 3.6

line equation

y =  \frac{2}{5} x + 3.6

4 0
3 years ago
The levels of mercury in two different bodies of water are rising. In one body of water the initial measure of mercury is 0.05 p
NNADVOKAT [17]

Answer:

0.05 + 0.1y = 0.12 + 0.06y

Step-by-step explanation:

Here, we want to find y which is the heat in which the amount of mercury in each of the water bodies is same.

Now for the first water body:

Initial is 0.05 ppb and after y years, we have a rise of 0.1 * y = 0.1y ppb

So the amount of mercury in ppb after y years would be; 0.05 + 0.1y

For the second water body;

Initial is 0.12 and a rise of 0.06 ppb per year for y years. The rise would be 0.06 * y = 0.06y

So total amount of mercury here is 0.12 + 0.06y

So to find y which is the year the amount of mercury in each water body is same, we simple equate both and that would be;

0.05 + 0.1y = 0.12 + 0.06y

4 0
3 years ago
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