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2 years ago

Can you help me please

Mathematics

1 answer:

Olin [163]2 years ago

3 0

Answer:

(2,1)

Step-by-step explanation:

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830000 in scientific notation

DedPeter [7]

Answer:

8.3 * 10 ^5

Step-by-step explanation:

830000

To change this to scientific notation, we move the decimal 5 places to the left. The exponent will be positive 5 because we moved it to the left

8.3 * 10^ +5

8.3 * 10 ^5

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7Bx%7D%7B19%7D%20%20%3D%206" id="TexFormula1" title=" \frac{x}{19} = 6" alt=" \fra

Alex17521 [72]

[ Answer ]

$\boxed{X \ = \ 114}$

[ Explanation ]

$\frac{x}{19}$ = 6

Multiply Both Sides By 19

$\frac{x}{19}$ = 6 · 19

Simplify:

X = 114

Check Your Work:

$\frac{114}{19}$

Simplify:

= 6

$\boxed{[ \ Eclipsed \ ]}$

5 0

2 years ago

If f(x) and its inverse function, F(x), are both plotted on the same coordinate plane, what is their point of intersection?

polet [3.4K]

Answer: d) (3, 3)

<u>Step-by-step explanation:</u>

Inverse is when you swap the x's and y's.

Let's look at the points and find their inverse:

f(x) f⁻¹(x)

(0, -2) --> (-2, 0)

(1, -1) --> (-1, 1)

(2, 0) --> (0, 2)

(3, 3) --> (3, 3) f(x) = f⁻¹(x) so this is where they intersect!

5 0

3 years ago

HELP!!!! Solve for y in the following equation: -4y + 9 = -28

Flura [38]

Answer:

y = 37/4

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Lucy’s chocolate bar is 54% cocoa. If the weight of the chocolate bar is 54 grams, how many grams of cocoa does it contain? Roun

Masteriza [31]

Answer:

The chocolate bar contains 29.2 grams of cocoa.

Step-by-step explanation:

Given that Lucy’s chocolate bar is 54% cocoa and the weight of the chocolate bar is 54 grams.

Hence, the amount of cocoa in the chocolate bar is given by

54% of 54 grams

54% percentage means 54/100 = 0.54

Hence, the amount of cocoa in the chocolate bar is

$0.54\times54\\=29.16$

When rounded to the nearest tenth, 29.16 should be equal to 29.2

Hence, the chocolate bar contains 29.2 grams of cocoa.

4 0

2 years ago

Can you help me please ​

Can you help me please