Which of the above polynomials is a 5th degree trinomial?

1 answer:

7 0

Easy

5th degree means highest power is 5 so must have x^5

trinomial means 3 terms

A. trinomial, highes power is 5, check
b. trinomial, highest power is 3, nope
c. not a trinomial, highest power is 3, nope
d. not a trinoial, highest power is 5, nope

answer is A

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56 - (n + 4) For n = 44

loris [4]

Pretty sure the answer is 8

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3 years ago

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45^2 ÷ 78 = ????????

elena55 [62]

$\frac{(45)^2}{78}$

To solve the problem find the value of (45)^2 at first

$(45)^2=2025$ $\frac{2025}{78}=25\text{ R75}$

The answer is 25 with the remainder 75

$25\frac{75}{78}$

You can simplify the fraction to be 25/26

$25\frac{25}{26}$

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1 year ago

Graph the function and analyze it for domain, range, continuity, increasing or decreaseing behavior, symmetry, boundedness, extr

Sunny_sXe [5.5K]

Answer:

$f(x) = 3 \cdot 0.2^x$

Step-by-step explanation:

$f(x) = 3 \cdot 0.2^x$

Domain of f: "What values of x can we plug into this equation?" This makes sense for all real numbers so the domain is $\mathbb{R}$

Range of f: "What values of f(x) can we get out of the function?" From the graph we see we can get any real number greater than 0 out of the function by choosing a suitable x-value in the domain. The range is therefore $(0, \infty)$ .

Continuity: Since the graph is one, unbroken curve (i.e. a curve that can be drawn in one movement without taking your pen off the paper). We see that "roughly speaking" the function is continuous.

Increasing or decreasing behaviour: For all x in the domain, as x increases, f(x) decreases. This means the function exhibits decreasing behaviour.

Symmetry: It is clear to see the graph of f(x) has no symmetry.

Boundedness: Looking at the graph we see it is unbounded above as when we choose negative values, the graph of f(x) explodes upwards exponentially. Choose a value of x, plug it in, next choose (x-1), plug this in and we observe $f(x-1) > f(x)$ for all x in the domain.

The function is however bounded below by 0: no value of x in the domain exists which satisfies $f(x) < 0$ .

Extrema: As far as I can tell, there are no turning points on the curve. (Is this what you mean by extrema?)

Asymptotes: Contrary to the curve's appearance, there are no vertical asymtotes for this curve. The negative-x portion of the curve is just growing so quickly it appears to look like an asymptote. There is a value of f(x) for all x<0. There is however a horizontal asymtote: $y=0$ .