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Sveta_85 [38]
3 years ago
9

Write an equation in slope-intercept form for the line with slope -2/3 and y-intercept -4.

Mathematics
1 answer:
Natali [406]3 years ago
5 0

Step-by-step explanation:

Given

slope (m) = - 2/ 3

Y-intercept (c) = - 4

Now writing in Slope intercept form

y = mx + c

y =( - 2/3) x - 4

Hope it will help :)

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When the function f(x) = 3(5)x is changed to f(x) = 3(5)x + 22, what is the effect? (4 points) There will be no change to the gr
Dima020 [189]

Answer:

the y-intercept is 22 spaces higher.

Step-by-step explanation:

I don't know, what special operations you want to express with 3(5)x.

as it is written this simply means

3×5×x

no exponents or other special things are visible.

but it should not matter.

whatever is the first function is unchanged the first part of the second function.

so, the only difference is the "+ 22" part.

and that simply means that all y values (the functional result values) are increased by 22.

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2 years ago
Simplify: 6w4 + 11w4.<br> Enter the original expression if it cannot be<br> simplified.
yulyashka [42]

Answer:

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Step-by-step explanation:

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3 years ago
[Algebra] Find the center and radius of the circle with equation x2 y2 -2x4y 113 op
KIM [24]
What you do is get into the form
(x-h)^2+(y-k)^2=r^2
(h,k) is center
r=radis

complete the square with x and y

x^2+y^2-2x+4y-11=0
group x and y terms together
(x^2-2x)+(y^2+4y)-11=0

take 1/2 of linear coefieicnt and add postive and negative
for x^2-2x, -2/2=-1, (-1)^2=1
for y^2+4y, 4/2=2, 2^2=4

(x^2-2x+1-1)+(y^2+4y+4-4)-11=0
complete the square
(x-1)^2-1+(y+2)^2-4-11=0
add like terms
(x-1)^2+(y+2)^2-16=0
add 16 both side
(x-1)^2+(y+2)^2=16
(x-(1))^2+(y-(-2))^2=4^2
(x-h)^2+(y-k)^2=r^2

(h,k)
(1,-2)
r=4

center is (1,-2)
radius is 4 units
7 0
3 years ago
Read 2 more answers
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