Answer:
5
Step-by-step explanation:
-1+5+6-5
-1-5+5+6
-6+11
5
100%=900
1%=9
750÷9=83.333...
750=83%
Answer:
See explanations below
Explanation:
Vertex of a graph is the lowest point on the curve. The vertex occurs at (1.75, -2.5)
The axis of symmetry is the point on the x axis of the line that cuts through the minimum point. The axis of symmetry occurs at x = 1.75
x intercept is the point where the curve cuts the x axis. The x intercept occurs at x = 0 and x = 2.5
To get the minimum, we will use the formula;
c - b^2/4a
The equation of the curve is expressed as;
(x-0)(x-2.5)
= x (x-2.5)
= x^2 - 2.5x
a = 1, b = -2.5, c = 0
minimum = 0 - (-2.5)^2/4(1)
minimum = -6.25/4
minimum = -1.5625
Minimum value occurs at the base of the parabola. The minimum value of the function is -2.5
y intercept is the point where the curve cuts the y axis. The y-intercept occurs at y = 0.
Answer:
The answer is B (From the cup to the hand)
Step-by-step explanation:
Answer:
![3 + \frac{1}{2\sqrt{3} } + \frac{1}{5\sqrt[5]{81} }](https://tex.z-dn.net/?f=3%20%2B%20%5Cfrac%7B1%7D%7B2%5Csqrt%7B3%7D%20%7D%20%2B%20%5Cfrac%7B1%7D%7B5%5Csqrt%5B5%5D%7B81%7D%20%7D)
Step-by-step explanation:
Just to make it easier to see, 
and ![\sqrt[5]{x} = x^{\frac{1}{5} }](https://tex.z-dn.net/?f=%5Csqrt%5B5%5D%7Bx%7D%20%3D%20x%5E%7B%5Cfrac%7B1%7D%7B5%7D%20%7D)
This way we could more easily use the power rule of derivatives.
So if f(x) = 
then f'(x) will be as follows.
f'(x) = ![x^{1} +\frac{1}{2} x^{-\frac{1}{2} } +\frac{1}{5} x^{-\frac{4}{5} } = x +\frac{1}{2x^{\frac{1}{2} }} +\frac{1}{ 5x^{\frac{4}{5} }} = x +\frac{1}{2\sqrt{x}} +\frac{1}{ 5\sqrt[5]{x^4} }](https://tex.z-dn.net/?f=x%5E%7B1%7D%20%2B%5Cfrac%7B1%7D%7B2%7D%20x%5E%7B-%5Cfrac%7B1%7D%7B2%7D%20%7D%20%2B%5Cfrac%7B1%7D%7B5%7D%20x%5E%7B-%5Cfrac%7B4%7D%7B5%7D%20%7D%20%3D%20x%20%2B%5Cfrac%7B1%7D%7B2x%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%7D%20%2B%5Cfrac%7B1%7D%7B%205x%5E%7B%5Cfrac%7B4%7D%7B5%7D%20%7D%7D%20%3D%20x%20%2B%5Cfrac%7B1%7D%7B2%5Csqrt%7Bx%7D%7D%20%2B%5Cfrac%7B1%7D%7B%205%5Csqrt%5B5%5D%7Bx%5E4%7D%20%7D)
to find f'(3) just plug 3 into f'(x) so
