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3 years ago

4 The size 4 soccer ball Sean's team uses should weigh

Mathematics

1 answer:

Lina20 [59]3 years ago

5 0

Most 2 balls could weigh = 0.74 kilograms, Least 2 balls could weigh = 0.62 kilograms

Step-by-step explanation:

Maximum weight of soccer ball = 0.37 kilogram

Minimum weight of soccer ball = 0.31 kilogram

One bag has two balls

1. To find out the most weight, we need to assume that both balls are of the maximum weight so,

Weight of ball 1 + Weight of ball 2

0.37 + 0.37

= 0.74 kilograms

2. To find out the least weight, we need to assume that both balls are of the minimum weight so,

Weight of ball 1 + Weight of ball 2

0.31 + 0.31

= 0.62 kilograms

The weight of two balls are

$\leq 0.74 kilograms$

$\geq 0.62 kilograms$

Therefore, the most these two balls could weigh together is 0.74 kilograms and the least these two balls could weigh together is 0.62 kilograms.

Key words: weight

Learn more about the topic of calculating weights on brainly.com/question/663692

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Helena uses a mixture of compost and topsoil in her garden. She purchased a total of 10 cubic yards of compost and topsoil for $

Annette [7]

Let C be the amount of compost

T be the amount of topsoil

Each compost cost = $25

Cost of C compost = 25C

Each topsoil cost = $15

Cost of T topsoil = 15T

Amount of compost + amount of topsoil = 10

C + T = 10 -------> Equation 1

cost of C compost + cost of T topsoil = 180

25C + 15T = 180 --------> equation 2

Solve the first equation for C

C + T = 10

C = 10 - T

Now plug it in second equation

25C + 15T = 180

25 ( 10 - T) +15T = 180

250 - 25T + 15T = 180 (combine like terms)

250 - 10 T = 180 (Subtract 250 on both sides)

-10T = 180 - 250

-10T = -70 ( divide by -10 on both sides)

T = 7

She purchased 7 cubic yards of topsoil .

4 0

3 years ago

Read 2 more answers

Angle Addition Crossword

Elena-2011 [213]

Answer:

Step-by-step explanation:

1). m∠AEC = m∠AEB + m∠BEC

= 21° + 37°

= 58°

2). m∠BED = m∠BEC + m∠CED

= 37° + 44°

= 81°

3). m∠IKF = m∠IKH + m∠HKG + m∠GKF

= m∠IKH + m∠HKG + m∠IKH [Since, ∠IKH ≅ ∠GKF]

= 2∠IKH + m∠HKG

103° = 2∠IKH + 41°

2(∠IKH) = 103 - 41

m(∠IKH) = 31°

4). m∠AED = m∠AEB + m∠BEC + m∠CED

= 21° + 37° + 44°

= 102°

5). m∠JKG = 108°

m∠JKG = m∠JKI + m∠IKH + m∠HKG

108° = m∠JKI + 31° + 41°

m∠JKI = 108° - 72°

m∠JKI = 36°

6). m∠HKF = m∠GKF + m∠HKG

= m∠IKH + m∠HKG [Since, m∠GKF = m∠IKH]

= 31° + 41°

= 72°

7). m∠NQO = m∠MQN = 64°

8). m∠JKF = m∠JKI + m∠IKF

= 36° + 103°

= 139°

8). m∠MQO = 2(m∠NQO)

= 2(64)°

= 128°

9). m∠LQO = 156°

m∠LQM = m∠LQO - m∠MQO

= 156° - 128°

= 28°

10. m∠NQP = m∠NQO + m∠OQP

= 64° + m∠LQM [Since ∠OQP ≅ ∠LQM]

= 64° + 28°

= 92°

5 0

3 years ago

I’m confused on math ( combining like terms ) ?

maks197457 [2]

Answer:combining like terms is technically putting values that have the same variable (letter) Or numbers together to make a more simplified equation

Step-by-step explanation:

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2 years ago

Solve the equation by completing the square round to the nearest hundredth is necessary x^2-x-7=0

masha68 [24]

The answers are 3.19 or -2.19.

In order to complete the square, you must first get the constant to the other side of the equation. WE do that by adding 7 to both sides.

x^2 - x - 7 = 0

x^2 - x = 7

Now we must take half of the x coefficient (-1), which would be -.5. Then we square it and add it to both sides. This is the second step to any completing the square problem.

x^2 - x = 7

x^2 - x + .25 = 7.25

Now that we have done that, the left side will be a perfect square so that, we can factor it.

x^2 - x + .25 = 7.25

(x - .5)^2 = 7.25

After having done that, we can take the square root of both sides

(x - .5)^2 = 7.25

x - .5 = +/- $\sqrt{7.25}$

Now we can take the value of that square root and solve.

x - .5 = +/- $\sqrt{7.25}$

x - .5 = +/-2.69

x = .5 +/- 2.69

And with the + and - both there, we need to do both to get the two answers.

.5 + 2.69 = 3.19

.5 - 2.69 = -2.19

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2 years ago

What is the domain of the function y = -4x+1 if the range is -11

a_sh-v [17]

The range of a function is the set of all values that it can take when its independent variable takes values on the domain.

On the other hand, the range of a function is the domain of its inverse function, if that inverse exists, and vice-versa: the domain of a function is the range of its inverse function, if that inverse exists.

In the case of the given equation:

$y=-4x+1$

The inverse function exists since the function is linear, and it can be found by isolating x:

$x=-\frac{1}{4}(y-1)$

If the range of the original function is the set given by the number {

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1 year ago