<span>N(t) = 16t ; Distance north of spot at time t for the liner.
W(t) = 14(t-1); Distance west of spot at time t for the tanker.
d(t) = sqrt(N(t)^2 + W(t)^2) ; Distance between both ships at time t.
Let's create a function to express the distance north of the spot that the luxury liner is at time t. We will use the value t as representing "the number of hours since 2 p.m." Since the liner was there at exactly 2 p.m. and is traveling 16 kph, the function is
N(t) = 16t
Now let's create the same function for how far west the tanker is from the spot. Since the tanker was there at 3 p.m. (t = 1 by the definition above), the function is slightly more complicated, and is
W(t) = 14(t-1)
The distance between the 2 ships is easy. Just use the pythagorean theorem. So
d(t) = sqrt(N(t)^2 + W(t)^2)
If you want the function for d() to be expanded, just substitute the other functions, so
d(t) = sqrt((16t)^2 + (14(t-1))^2)
d(t) = sqrt(256t^2 + (14t-14)^2)
d(t) = sqrt(256t^2 + (196t^2 - 392t + 196) )
d(t) = sqrt(452t^2 - 392t + 196)</span>
Answer:
D. 
Step-by-step explanation:
We graph the points on the graph. The graph is attached.
Let us take two points (1, 14) and (15, 1), and calculate the slope 
between them <em>(we choose these points because the line passing through them will be the best fit for all points) </em>
Thus we have the equation
Let us now calculate 
from the point 
So the equation we get is
Let us now turn to the choices given and see which choice is closest to our equation: we see that choice D. is the closest one, so we pick it.
The triangle has to equal to 180. So add them up and equal it to 180
I hope i dont any mistake :p tell me if u dont understand :)
This is just to easy the correct answer is A
