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Andrej [43]
3 years ago
6

Solve the inequality. p + 14 ≥ 2

Mathematics
2 answers:
diamong [38]3 years ago
6 0

Answer:

p ≥ -12

Step-by-step explanation:

Original Equation:

p + 14 ≥ 2

Subtract 14 from both sides

p ≥ -12

Hope this helps :)

Please consider Brainliest :)

almond37 [142]3 years ago
3 0

Answer:

p \geq -12

Step-by-step explanation:

Subtract 14

p \geq -12

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What are the slope and the y- intercept of the linear function
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the slope is 9 and the y-intercept is - 2

the equation of a line in ' slope-intercept form ' is

y = mx + c ( m is the slope and c the y-intercept )

y = 9x - 2 is in this form

with slope m = 9 and y-intercept c = - 2



5 0
3 years ago
220% of the whole sale cost should not exceed the target retail price of $35
KatRina [158]
What exactly are you trying to solve? maybe i could help
7 0
3 years ago
What is the factored form of the expression. <br> 4n^2 + 24n + 36
skad [1K]

Answer:

(2n+6)^2

Step-by-step explanation:

To solve this, you can use the given formula: x^2 + 2xy + y^2

In this case, 4n^2 is x^2, 24n is 2xy, and 36 is y^2. The next step is:

(2n)^2 + 2(2n)(6) + (6)^2

Since this equation fits into this formula ( x^2 + 2xy + y^2), we can do:

(2n+6)(2n+6) =

(2n+6)^2

Hence, the answer is (2n+6)^2

6 0
3 years ago
(07.03 MC)
garri49 [273]

Answer:

9x²y¹⁴

Step-by-step explanation:

\tt (3xy^4)^2(y^2)^3\\\\=3^2x^2y^{4\cdot2}\cdot y^{2\cdot3}\\\\=9x^2y^{8}\cdot y^{6}\\\\= 9x^2y^{8+6}\\\\= 9x^2y^{14}

5 0
4 years ago
A greeting card has a perimeter of 80 cm and an area of 384 square cm what are the dimensions for the greeting card
Ulleksa [173]

Step-by-step explanation:

it is a rectangle (usually).

so,

2×length + 2×width = 80

therefore, length + width = 40

length×width = 384

length = 384/width

384/width + width = 40

384 + width² = 40×width

width² - 40×width + 384 = 0

the general solution for such a square equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

in our case

x = width

a = 1

b = -40

c = 384

width = (40 ± sqrt((-40)² - 4×1×384))/(2×1) =

= (40 ± sqrt(1600 - 1536))/2 =

= (40 ± sqrt(64))/2 = (40 ± 8)/2 =

= 20 ± 4

width1 = 20 + 4 = 24 cm

length1 = 40 - 24 = 16 cm

width2 = 20 - 4 = 16 cm

length2 = 40 - 16 = 24 cm

so, both solutions are the same.

the greeting card is 24×16 cm. or 16×24, depending on how you are holding it.

3 0
2 years ago
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