Evaluate 5x + 7 for x = - 2 plz help fastt
1 answer:
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The annual income of Janice when she accepts new job in Chicago be after paying rent, transportation, and food is, $409190.
<h3>What is the total cost?</h3>Total cost or the final cost is the summation of all the cost spend while buying any good or taking any service.
Janice has been offered a job in Chicago where her current salary of $30,000 will increase by 20 percent. Thus, his new salary is,
He gets 6000 thousand extra after increment. Her annual income is,
Before accepting the position, Janice wants to understand her potential cost of living.
- She estimates that rent will be $1,500 per month. Thus, the
- She will have to take the train to and from work, which will be $3.50 round trip daily.
- Her food cost will be $75 per week.
Janice works 5 days a week for 52 weeks per year. Her annual income be after paying rent, transportation, and food is,
Thus, the annual income of Janice when she accepts new job in Chicago be after paying rent, transportation, and food is, $409190.
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Complete Question:
In P2, find the change-of-coordinates matrix from the basis B = {1 − 3t² , 2+t− 5t² , 1 + 2t} to the standard basis C = {1, t, t²}. Then, write t² as a linear combination of the polynomials in B.
Answer:
The change of coordinate matrix is :
U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]
Step-by-step explanation:
Let U = {D, E, F} be any vector with respect to Basis B
U = D [1 − 3t²] + E [2+t− 5t²] + F[1 + 2t]..............(*)
U = [D+2E+F]+ t[E+2F] + t²[-3D-5E]...................(**)
In Matrix form;
The change of coordinate matrix is therefore,
To find D, E, F in (**) such that U = t²
D + 2E + F = 0.................(1)
E + 2F = 0.........................(2)
-3D -5E = 1........................(3)
Substituting eqn (2) into eqn (1 )
D=3F...................................(4)
Substituting equations (2) and (4) into eqn (3)
-9F+10F=1
F = 1
Put the value of F into equations (2) and (4)
E = -2(1) = -2
D = 3(1) = 3
Substituting the values of D, E, and F into (*)
U = t² = 3 [1 − 3t²] - 2 [2+t− 5t²] + [1 + 2t]