Answer:
D
Step-by-step explanation:
D)y=6(x+1)²-16= 6(x²+2x+1)-16= 6x²+12x+6-16= 6x²+12x-10
<span>answer: D</span>
Answer:
2630 g
Step-by-step explanation:
From the given information:
Given that:
mean (μ) = 3750 g
Standard deviation (σ) = 500
Suppose the hospital officials demand special treatment with a percentage of lightest 3% (0.03) for newborn babies;
Then, the weight of birth that differentiates the babies that needed special treatment from those that do not can be computed as follows;
P(Z < z₁) = 0.03
Using the Excel Formula; =NORMSINV(0.03) = -1.88
z₁ = - 1.88
Using the test statistics z₁ formula:


By cross multiply, we have:
-1.88 × 500 = X - 3570
-940 = X - 3570
-X = -3570 + 940
-X = -2630
X = 2630 g
Hence, 2630 g is the required weight of birth that differentiates the babies that needed special treatment from those that do not
So you want to know how much was paid in total?
First, how much is 18% of 43?
43*0.18 =8.64
so the total prize will be the sum of the gratuty and the dinner prize: 43+8.64=51.64
and this is the solution!