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poizon [28]
2 years ago
7

How can you use the pythagorean theorem to solve real-world problems

Mathematics
2 answers:
neonofarm [45]2 years ago
8 0
<span>Painters use ladders to paint on high buildings, and they use Pythagoras theorem to complete their work. </span>
melisa1 [442]2 years ago
6 0
The Pythagorean theorem is used in most physics problems for vectoring as well as being incredibly important in proving calculus, the Pythagorean theorem is likely one of the most critical things ever put together and most later math is based heavily upon it.
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What is 1+1. Thank you
scoundrel [369]

Answer:

2

Step-by-step explanation:

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2 years ago
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Which set of lengths are the side lengths of a right triangle? (9,15,17) (14,23,25) (20,30,40) (15,36,39)
goldfiish [28.3K]

Answer:

(15, 36, 39)

Step-by-step explanation:

Using pythagoreas formula: A^2 * B^2 = C^2

so a=15, b=36, c=39

15^2+36^2=39^2

6 0
3 years ago
A graduated cylinder that is 24 cm tall can hold 1 L of water.
shutvik [7]

Answer:

LOL i belive its 200 because i did this exact same thing yesterday for homework and got it right, if its not then i dont know what to say.

Step-by-step explanation:

8 0
3 years ago
Koto’s average velocity along her route was 4. 5 m/s. She started at her house and traveled 15,000 meters north, 5,000 meters ea
Lostsunrise [7]

The time taken for her trip is 3 hours.

<h3>Given that</h3>

Koto’s average velocity along her route was 4. 5 m/s.

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3>We have to determine</h3>

What was the time of her trip?

<h3>According to the question</h3>

She started at her house and traveled 15,000 meters north, 5,000 meters east, 20,000 meters south, and then 5,000 meters west.

<h3 /><h3>The calculation of such a trip of Koto can be done by applying the known formula of Time when the Speed is multiplied by Distance to compute the actual time of the trip.</h3>

The formula to calculate the time for her trip is;

\rm Speed = \dfrac{ Distance}{Time}\\&#10;\\&#10;Time = \dfrac{Distance}{Speed}\\&#10;\\&#10;

  • Using the formula above, the commute in each direction is added as 45000 meters or 45 kilometers.

  • If Koto's average speed is 4.5 meters per second, then she travels roughly 270 meters in one minute.

Substitute all the values in the formula;

\rm\ Time = \dfrac{Distance}{Speed}\\\\  Time = \dfrac{45000}{270}\\&#10;\\&#10;Time =166.7

Converting minutes into hours,

\rm Hours = \dfrac{Minute}{60}\\&#10;\\&#10;Hours = \dfrac{166.7}{60}\\&#10;\\&#10;Hours = 2.77 \\&#10;\\&#10;= 3\  hours

Hence, the time taken for her trip is 3 hours.

To know more about Time and Distance click the link given below.

brainly.com/question/4433818

5 0
2 years ago
Needhdjdjdjdjdjdnhiskdjdjdjdjdjdjjshdjdjdjdjdjdjdjd<br><br>​
Lilit [14]

9514 1404 393

Answer:

  -(√2)/2

Step-by-step explanation:

The expression evaluated at n=a gives the indeterminate form 0/0, so L'Hopital's rule can be used to find the limit. The second expression comes from differentiating numerator and denominator. Then the form with n=a is no longer indeterminate.

  \displaystyle\lim_{n\to a}{\frac{\sqrt{2n}-\sqrt{3n-a}}{\sqrt{n}-\sqrt{a}}}=\lim_{n\to a}{\frac{\frac{2}{2\sqrt{2n}}-\frac{3}{2\sqrt{3n-a}}}{\frac{1}{2\sqrt{n}}-0}}\\\\=\sqrt{a}\left(\frac{2}{\sqrt{2a}}-\frac{3}{\sqrt{3a-a}}}\right)=\boxed{-\frac{1}{\sqrt{2}}}

5 0
2 years ago
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