Answer:
0.1587
Step-by-step explanation:
Given the following :
Mean (m) of distribution = 64 inches
Standard deviation (sd) of distribution = 2 inches
Probability that a randomly selected woman is taller than 66 inches
For a normal distribution :
Z - score = (x - mean) / standard deviation
Where x = 66
P(X > 66) = P( Z > (66 - 64) / 2)
P(X > 66) = P(Z > (2 /2)
P(X > 66) = P(Z > 1)
P(Z > 1) = 1 - P(Z ≤ 1)
P(Z ≤ 1) = 0.8413 ( from z distribution table)
1 - P(Z ≤ 1) = 1 - 0.8413
= 0.1587
Answer:
ans: coefficient of 3rd term is 60
3rd term is 60x
Step-by-step explanation:
(5x +2)³ = C(3,2) × (5x)^(3-2) × 2²
= 3 × 5 × 4 × x
= 60x
The equation relating length to width
L = 3W
The inequality stating the boundaries of the perimeter
LW <= 112
When you plug in what L equals in the first equation into the second equation, you get
3W * W <= 112
evaluate
3W^2 <= 112
3W <=

W <=

cm
100 is the correct answer to your question
Answer:
159 m
Step-by-step explanation:
From the information given:
It was stated that if the ostrich ran towards the east direction in 7.95 s, let say the distance from the starting point is O towards the east side E, let called the distance towards the east side to be OE.
Again, the ostrich then runs in the south direction for 161 m, let the distance be OS.
Also, let the magnitude of the resultant displacement between the east direction to the south direction be ES = 226m.
We are to find, the magnitude of the ostrich's eastward component.
i.e. The distance traveled from the center to the east direction within the time frame of 7.95 s.
Using the Pythagoras rule:
ES² = OE² + OS²
226² = OE² + 161²
226² - 161² = OE²
OE² = 226² - 161²
OE² = 51076 - 25921
OE² = 51076 - 25921
OE² = 25155

OE = 158.60 m
OE ≅ 159 m
Thus, the magnitude of the ostrich's towards the eastward component. = 159 m.