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Vikentia [17]
2 years ago
7

Make the subject of the formular A=arh C=2Ar​

Mathematics
1 answer:
prohojiy [21]2 years ago
3 0

Answer:

Step-by-step explanation:

I think this is it but you question want super clear

A = C/2r

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Entre Juan, Pedro, María y Luis tienen 62 cartas. Pedro tiene un tercio de las cartas de Juan. María tiene 3 cartas menos que Ju
fenix001 [56]

Answer:

Luis has 30 cards

Step-by-step explanation:

To solve this problem, we need to setup a system of equations.

If we call the amount of cards Juan has "J", Pedro "P", Maria "M" and Luis "L", we have that:

J + P + M + L = 62

P = J/3

M = J - 3

L = 2J

Substituting P, M and L in the first equation, we have:

J + J/3 + J - 3 + 2J = 62

13J/3 = 62 + 3

13J = 65 * 3

J = 15 cards

The amount of cards Luis has is:

L = 2J = 2 * 15 = 30 cards

8 0
3 years ago
Lin took 75 boxes of carrots and 80 boxes of potatoes to the market. She sold 68 boxes of carrots and 71 boxes of potatoes. How
Lady bird [3.3K]

Answer:

16

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Solve y=x^​2+23 for x
Step2247 [10]
The answer to this is oh nvm

8 0
3 years ago
Jill earn $15 per hour babysitting class a transportation fee of five dollars per job. Write a formula for E, Ji Jill earn $15 p
daser333 [38]
Since you know the amount of what she earns you would use the number 15 and you dont know how long she worked you would put "x" next to the 15. so you would have 15x and then put a plus 5 to show her transportation fee. so you would have the equation of 15x+5:) and instead of x use h to show hours because h=hours

you feel me?
great!
6 0
3 years ago
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for the function. (
Mrrafil [7]

Answer:

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

Step-by-step explanation:

From exercise we have the next function y = 6 sec(3x).

We know that Maclaurin series for the function sec x, have the following form:

\sec x=1+\frac{x^2}{2}+\frac{5x^4}{24}+...

So, for the given function y = 6 sec(3x), we get:

y = 6 \sec(3x)=6+27x^2+\frac{405x^4}{4}+...

So, the first three nonzero terms in the Maclaurin series are:

6, \, 27x^2, \, \frac{405x^4}{4}.

6 0
3 years ago
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