Answer:
Step-by-step explanation:
Let "Hannah" = h, and her sister = s
h = 2s
h + s ≤ 18
Plug in 2s for h in the second equation.
(2s) + s ≤ 18
Simplify
2s + s ≤ 18
3s ≤ 18
Isolate the variable (s). Divide 3 from both sides
(3s)/3 ≤ (18)/3
s ≤ 18/3
s ≤ 6
2) The oldest Hannah's sister can be is <em>6 years</em>
<em>~</em>
[4 - (3c - 1)][6 - (3c - 1)]
[4 - 3c + 1][6 - 3c + 1]
[-3c + 4 + 1][-3c + 6 + 1]
[-3c + 5][-3c + 7]
-3c[-3c + 7] + 5[-3c + 7]
-3c[-3c] - 3c[7] + 5[-3c] + 5[7]
9c² - 21c - 15c + 35
9c² - 36c + 35
(4x^2 - 25)/(2x-5) =( 4x^2 - 25)/(2x - 5)
=( 2x)^2 -5^5/ (2x - 5)
=(2x -5)(2x + 5)/ (2x - 5) { deferense with square two numbers}
=(2x + 5)//
Answer:
No
Step-by-step explanation: