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Trava [24]
2 years ago
8

How many solutions will the system of equations have? System: y = 2x + 2 and y = x + 4

Mathematics
1 answer:
vivado [14]2 years ago
6 0
Y=-2x+2
y=x2-2x+4

is the value of x such that when you plug it into both equations, they both produce the same value of y, or the value of x such that

-2x+2=x2-2x+4

solving this equation----------> x2=-2, taking square root of both sides gives x= ±√2i, or the system has no real solutions but has 2 complex solutions. If you graph both functions in the xy-plane, where x, y are real numbers, you' ll see they do not intersect, which implies there is no real number solutions.
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DJ Mykel is making a playlist for a radio show; he is trying to decide what 14 songs to play and in what order they should be pl
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Answer:

5878600 different playlists.

Step-by-step explanation:

Since we require 14 songs for the playlist and there are 7 hip-hop, 5 jazz, 7 pop, and 8 blues songs, and DJ Mykel wants to play no more than 3 hip-hop songs, the number of ways in which he can combine the 7 hip-hop songs to play no more than 3 is ⁷C₃ = 7!/4!3!.

Now, since we have 3 songs already selected, we are left with 14 - 3 = 11 songs to select.

Since we have selected the 3 hip-hop songs, we are left with 5 jazz, 7 pop, and 8 blues songs which sum to a total of 20 songs.

So, we have 20 songs to select in 11 ways which is ²⁰C₁₁ = 20!/(20 - 11)!11! = 20!/9!11!

So, the number of different playlists that can be formed is thus

⁷C₃ × ²⁰C₁₁ =  7!/4!3!.× 20!/9!11!

= 35 ×  167960

= 5878600 different playlists.

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