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11Alexandr11 [23.1K]
3 years ago
7

Is the graph proportional or non-proportional, and if so, why?

Mathematics
1 answer:
Aneli [31]3 years ago
7 0

Explanation is in the file

tinyurl.com/wpazsebu

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What is the value of pi (i need to unlock the safe because is an inhibitor there) DYING LIGHT 2
Shtirlitz [24]

The number π (pi) is a mathematical constant which is equal to the ratio of a circle's circumference to its diameter. It has a value of π = 22/7

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

The number π (pi) is a mathematical constant which is equal to the ratio of a circle's circumference to its diameter. It is given by:

π = 22/7

Find out more on equation at: brainly.com/question/2972832

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What is the reason for each step in the solution of the equation?
kobusy [5.1K]
4x − 1 = −2 (x + 1) ⇒ Given

4x−1=−2x−2⇒ Distributive property (since we've multiplied out -2(x+1))

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</span>6x=−1 ⇒ <span>Commutative Property (We've moved -1 to the other side to get the sum -2+1 = -1)

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4 years ago
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PLS HELP ITS DUE IN 3 MINUTES
jek_recluse [69]

Answer:

H 33 degrees

Step-by-step explanation:

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3 years ago
RHOMBUS The diagonals of rhombus ABCD intersect at E. Given that
schepotkina [342]

Answer:

<u>Question 11:</u>

\angle DAC = 53^\circ

\angle AED = 90^\circ

\angle ADC = 74

DB = 16

AE = 6.03

AC = 12.06

<u>Question 12:</u>

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

Step-by-step explanation:

<u>Question 11</u>

Given

\angle BAC = 53^\circ

DE = 8

See attachment for Rhombus

Required

Determine the indicated sides

Solving (a): \angle DAC

Diagonal CA divides \angle DAB into 2 equal angles

i.e

\angle DAC = \angle BAC

So:

\angle DAC = 53^\circ

Solving (b): \angle AED

The angles at E is 90 degrees because diagonals AC and BD meet at a perpendicular.

So:

\angle AED = 90^\circ

Solving (c): \angle ADC

First, we calculate \angle ADE, considering \triangle ADE:

\angle ADE + \angle AED + \angle DAC = 180

\angle ADE + 90 + 53 = 180

\angle ADE + 143 = 180

\angle ADE = -143 + 180

\angle ADE = 37

To calculate \angle ADC, we have:

\angle ADC = 2*\angle ADE

\angle ADC = 2* 37

\angle ADC = 74

Solving (d): DB

From the rhombus

DB = DE +EB

Where

DE =EB

So:

DB = 8 + 8

DB = 16

Solving (e): AE

To do this we consider \triangle ADE

Using the tan formula

tan(\angle ADE) = \frac{AE}{DE}

\angle ADE = 37 and DE = 8

So:

\tan(37) = \frac{AE}{8}

AE = 8 * \tan(37)

AE = 6.03

Solving (f): AC

This is calculated as:

AC = AE + EC

Where

AE = EC

AC = 6.03 +6.03

AC = 12.06

<u>Question 12: Isosceles Triangle</u>

In the rhombus, all 4 sides are equal;

So, the isosceles triangle are:

\triangle ABD, \triangle BAC, \triangle CDA and \triangle DAB

<u>Question 13: </u>

AC and BD are perpendicular lines, and they are diagonals

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swer:

Step-by-step explanation:

I know the answer is b

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