Question

I need help with these 4 questions on my math homework! I have some examples with it but I still don't know how to do them... (Solved)

Answer 1

Step-by-step explanation:

For equation N°2

$-x-3 = 0$

Solving algebraically:

$-x + x -3 = x$ (Sum x on both sides of the equation)

$-3 = x$

Resolving graphically:

x = -2 --------- - (- 2) -3 = -1 pto (-2, -1)

x = -4 ---------- - (- 4) -3 = 1 pt (-4.1)

x = -3 --------- - (- 3) -3 = 0 pt (-3.0) Solution

The graphic is shown in the attached image. The red dot in the graph represents the solution

For equation N° 4

$9x +3 = 0$

Solving algebraically:

$9x+3 -3 = -3$ (Sum -3 on both sides of the equation)

$9x =-3$

$\frac{9x}{9}=\frac{-3}{9}$ (divided by 9 on both sides of the equation)

$x =\frac{-3}{9}$ (simplifies the fraction)

$x =\frac{-1}{3}$

Resolving graphically:

x = 1 --------- 9 (1) +3 = 12 pt (1.12)

x = -1 --------- 9 (-1) +3 = -6 pto (-1, -6)

x = -1 / 3 -------- 9 (-1/3) +3 = 1 pt (-1 / 3.0) Solution

The graphic is shown in the attached image. The red dot in the graph represents the solution

For equation N°. 6.

$4x + 11 = 4x-24$

Solving algebraically:

$4x -4x +11 = 4x -4x-24$ (Sum -4x on both sides of the equation)

$11 = -24$ The equation is not met, the x are eliminated, therefore, it has solution

For equation N°. 8

$-6x +3 = -6x + 5$

Solving algebraically:

$-6x + 6x +3 = -6x + 6x +5$ (Sum 6x on both sides of the equation)

$3 = 5$ The x are eliminated, 3 is not equal to 5, the equality is not met. The equation has no solution.