Answer:

• let f(x) be m:

• make x the subject of the function:
![{ \rm{8m = {x}^{3} + 128}} \\ \\ { \rm{ {x}^{3} = 8m - 128 }} \\ \\ { \rm{ {x}^{3} = 8(m - 16) }} \\ \\ { \rm{x = \sqrt[3]{8} \times \sqrt[3]{(m - 16)} }} \\ \\ { \rm{x = 2 \sqrt[3]{(m - 16)} }}](https://tex.z-dn.net/?f=%7B%20%5Crm%7B8m%20%3D%20%20%7Bx%7D%5E%7B3%7D%20%20%2B%20128%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7B%20%7Bx%7D%5E%7B3%7D%20%3D%208m%20-%20128%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7B%20%7Bx%7D%5E%7B3%7D%20%3D%208%28m%20-%2016%29%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7Bx%20%3D%20%20%5Csqrt%5B3%5D%7B8%7D%20%20%5Ctimes%20%20%5Csqrt%5B3%5D%7B%28m%20-%2016%29%7D%20%7D%7D%20%5C%5C%20%20%5C%5C%20%7B%20%5Crm%7Bx%20%3D%202%20%5Csqrt%5B3%5D%7B%28m%20-%2016%29%7D%20%7D%7D)
• therefore:

Answer:
Step-by-step explanation:
The answer is 39, jk=18 because j multiplied by k is 18 and then i added 3 and i got 21, then k (6) multiplied by 3 is 18, so then i added 21 and 18 and i got 39
There are several fractions that are equivalent to 4/5. Some are 8/10, 80/100, 800/1000. They all equal the same decimal: 0.8
Answer:
Step 1 is incorrect.
Step-by-step explanation:
The given expression is :

In step 1, Deepak rearranged the terms in order to simplify like terms together that is followed in step 2.
o, rearranging of the terms of an expression is commutative property and not distributive property. The distributive property is generally applicable to multiplication and is given as:

The commutative property is given as:
x+y = y +a
Therefore, adding terms by changing their order is commutative property of addition and not distributive property. Step 1 instruction is wrong.