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swat32
3 years ago
5

Write an equation in slope intercept form that passes through the points (-4,3) and (0,2)

Mathematics
1 answer:
Daniel [21]3 years ago
7 0

Answer:

y = -\frac{1}{4}x +2

Step-by-step explanation:

Slope-intercept form: y = mx + b

Slope formula: \frac{y2-y1}{x2-x1}

Given points: (-4, 3), (0, 2)

(0, 2) = (x1, y1)

(-4, 3) = (x2, y2)

To write the equation in slope-intercept form, we need to find the slope(m) and the y-intercept(b) of the equation.

First, let's find the slope. To do this, input the given points into the formula used to find slope:

\frac{3-2}{-4-0}

Simplify:

3 - 2 = 1

-4 - 0 = -4

\frac{1}{-4}= -\frac{1}{4}

The slope is -\frac{1}{4}.

To find the y-intercept, input the slope and one of the given points(in this example I'll use point (0, 2)) into the equation and solve for b:

2 = -\frac{1}{4} (0)+b

2 = 0 + b

2 = b

The y-intercept is 2.

Now that we know the slope and the y-intercept, we can write the equation:

y = -\frac{1}{4}x +2

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