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3 years ago

Solve the inequality and graph the solution.

Mathematics

1 answer:

rosijanka [135]3 years ago

5 0

Answer:

Solving the inequality $m - 6 > 2$ we get $\mathbf{m> 8}$

The graph is shown in figure attached.

Step-by-step explanation:

We need to solve the inequality and graph the solution.

$m - 6 > 2$

First solve the inequality

$m - 6 > 2\\$

Adding 6 on both sides

$m-6+6>2+6\\m>8$

Solving the inequality $m - 6 > 2$ we get $\mathbf{m> 8}$

Now, we will plot m > 8 on the graph

The graph is shown in figure attached

There will be an open circle on 8 as (m > 8) and line moves on right sides of 8.

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The probability of pulling an orange is 2 out of 5 if I 20 times how many of them would be orange

telo118 [61]

The answer would be 8.

4 0

3 years ago

What are the roots of y=x^2-3x

Crank

Answer:

Step-by-step explanation:

I believe that there was a typo in this question

Unfortunately, there are no roots of this equation without one of two things:

1. Another equation, and you could solve for the roots in a system of equations

2. The value of y is actually supposed to be 0

In the second case, you would solve it like this:

$x^{2}$ -3x = 0

factor out x

x(x-3) = 0

x = 0, x = 3

6 0

3 years ago

Mark and Trisha are traveling in the same direction and Mark is going 16 miles per hour. Trisha is going 12 miles per hour but s

Lorico [155]

Answer:

32 miles

Step-by-step explanation:

Given data

Let the total distance be x miles

Marks speed= 16miles per hour

Trisha's speed= 12 miles per hour

Trisha has covered 8 miles and has (x-8) miles to finish line

We know that

Speed= distance/time

time= distance/speed

Hence the time taken for Mark to finish is

time= x/16---------------1

The time taken for Trisha to finish is

time= (x-8)/12-----------2

equate 1 and 2 above

x/16= (x-8)/12

cross multiply

16(x-8)= 12*x

16x-128= 12x

collect like terms

16x-12x= 128

4x=128

x= 128/4

x= 32 miles

Hence they will meet at exactly 32 miles along the way

5 0

3 years ago

IQ scores for adults age 20 to 34 years are normally distributed according to N(120, 20). In what range does the middle 68% of p

Ilya [14]

The required interval of the given normal distribution using the empirical rule is <u>[100, 140]</u>.

The empirical rule formula (also known as a 68 95 99 rule formula) uses data from a normal distribution to determine the first, second, and third standard deviations, which, respectively, differ from the mean value by 68%, 95%, and 99%. Additionally, it shows that 99.9% of the data fall inside the third standard deviation range (either above or below the mean value). The empirical rule formula is described below with cases that have been resolved.

In the question, we are given that IQ scores for adults aged 20 to 34 years are normally distributed according to N(120, 20), and are asked for the range in which the middle 68% of people in this group score on the test.

N(120, 20) signifies a normal distribution with mean, μ = 120, and the standard deviation, σ = 20.

By the empirical formula, 68% of the data lies within one standard deviation from the mean.

Thus, the required interval is [μ - σ, μ + σ] = [120 - 20, 120 + 20] = [100, 140].

Learn more about the empirical rule at

brainly.com/question/10093236

#SPJ4

6 0

1 year ago

Jacob solves the system of equations by forming a matrix equation.

Lyrx [107]

Simultaneous equations can be solved using inverse matrix operation.

The complete steps of Jacob's solution are:

$\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]^{-1} \cdot \left[\begin{array}{cc}4&1\\-2&3\end{array}\right]\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14}\left[\begin{array}{cc}3&-1\\2&4\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]$

We have:

$4x + y = 2$

$-2x + 4y = -22$

Calculate the determinant of $\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]$

$|A| = 4 \times 3 -1 \times -2$

$|A| = 12 +2$

$|A| = 14$

So, the inverse matrix becomes

$A = \frac{1}{14}\left[\begin{array}{cc}4&1\\-2&3\end{array}\right]$

Replace the first column with $\left[\begin{array}{c}2&-22\end{array}\right]$ to calculate the value of x

$x = \frac{1}{14}\left[\begin{array}{cc}2&1\\-22&3\end{array}\right]$

So, we have:

$x = \frac{1}{14}(2 \times 3 - 1 \times -22)$

$x = \frac{1}{14}(6 +22)$

$x = \frac{1}{14}(28)$

$x = 2$

Replace the second column with $\left[\begin{array}{c}2&-22\end{array}\right]$ to calculate the value of y

$y = \frac{1}{14}\left[\begin{array}{cc}4&2\\-2&-22\end{array}\right]$

So, we have:

$y = \frac{1}{14}(4 \times -22 - 2 \times -2)$

$y = \frac{1}{14}(-88 +4)$

$y = \frac{1}{14}(-84)$

$y = -6$

Hence, the complete process is:

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{cc}4&1\\-2&3\end{array}\right] \cdot \left[\begin{array}{c}2&-22\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \frac{1}{14} \left[\begin{array}{c}28&-84\end{array}\right]$

$\left[\begin{array}{c}x&y\end{array}\right] = \left[\begin{array}{c}2&-6\end{array}\right]$