Draw a diagram to illustrate the problem as shown below.
Let v = speed of the westbound car, mph
Because the eastbound car travels 4 mph faster than the westbound car, its speed is (v+4) mph.
After 2 hours,
the westbound car travels 2v miles west, and the eastbound car travels 2(v+4) miles east.
Because they become separated by 208 miles, therefore
2v + 2(v+4) = 208
4v + 8 = 208
4v = 200
v = 50 mph
The westbound car travels at 50 mph.
The eastbound car travels at v+4 = 54 mph
Answer: The eastbound car travels at 54 mph.
An angle of elevation of 58 degrees with the ground means
that the angle started at the x-axis and terminates on the first quadrant
region through a counter clockwise direction. Imagining a triangle, the string
of the kite becomes the hypotenuse, the angle 58 degrees is the angle between
the hypotenuse and the ground, and the height of the kite is the side opposite
to the angle.
Therefore, we can calculate for the height of the kite
using the sin function:
sin θ = opposite side / hypotenuse
sin 58 = opposite side / 50 m
opposite side = 50 m * sin 58
opposite side = 42.4 m
<span>Therefore the kite is about 42.4 m above the ground.</span>
X = 77.789
y = 23...............................
Answer:
9 + 0.0 + 0.07 + 0.006
Step-by-step explanation:
9 + 0.0 + 0.07 + 0.006