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Shkiper50 [21]
2 years ago
10

A triangle has an area of 117.9 square millimeters and a base of 18 millimeters. What is the height?

Mathematics
2 answers:
morpeh [17]2 years ago
5 0

Answer:

13.1

Step-by-step explanation:

mr Goodwill [35]2 years ago
4 0
The correct answer is 13.1
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The smaller of two numbers is one-half the larger, and their sum is 27. Find the numbers. I need an answer in 10 minutes
Alex777 [14]

Answer:

18 and 9

Step-by-step explanation:

The numbers are x and 1/2x.

x + 1/2x = 27

3/2x = 27

x = 18 so the numbers of 18 and 9.

6 0
3 years ago
Give the value of x .<br><br> A. 60 degrees<br> B. 180 degrees<br> C. 120 degrees<br> D. 45 degrees
Harrizon [31]

Answer:

x=120°

Step-by-step explanation:

sum of all angles in a triangle is equal to 180

let the unknown angle be

\alpha

60 + 60 +  \alpha  = 180 \\  \alpha  = 180 - 60 - 60 \\  \alpha  = 60 \\

\alpha  + x = 180 \\ x = 180 -  \alpha  \\ x = 180 - 60 \\ x = 120

5 0
2 years ago
Geometry help! Picture included :)
AURORKA [14]
Set up a proprtion and cross multiply.

18/7.5=22/4x+1

7.5×22=18 (4x+1)
165=72x+18
147=72x
x=2.04
8 0
3 years ago
I need help with math
Mashutka [201]

Answer:

45%

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
According to a recent​ publication, the mean price of new mobile homes is ​$63 comma 800. Assume a standard deviation of ​$7900.
wolverine [178]

Answer:

a. For n=25, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,580​, respectively.

b. For n=50, the mean and standard deviation of the prices of the mobile homes all possible sample mean prices are ​$63,800 and ​$1,117​, respectively.

Step-by-step explanation:

In this case, for each sample size, we have a sampling distribution (a distribution for the population of sample means), with the following parameters:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{n}

For n=25 we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{25}=7,900/5=1,580

The spread of the sampling distribution is always smaller than the population spread of the individuals. The spread is smaller as the sample size increase.

This has the implication that is expected to have more precision in the estimation of the population mean when we use bigger samples than smaller ones.

If n=50, we have:

\mu_s=\mu=63,800\\\\\sigma_s=\sigma/\sqrt{n}=7,900/\sqrt{50}=7,900/7.07=1,117

4 0
3 years ago
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